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sweet [91]
2 years ago
13

An green hoop with mass mh = 2.8 kg and radius rh = 0.17 m hangs from a string that goes over a blue solid disk pulley with mass

md = 1.8 kg and radius rd = 0.08 m. the other end of the string is attached to a massless axle through the center of an orange sphere on a flat horizontal surface that rolls without slipping and has mass ms = 3.6 kg and radius rs = 0.2 m. the system is released from rest. 1) what is magnitude of the linear acceleration of the hoop
Physics
1 answer:
vladimir2022 [97]2 years ago
6 0
The mass of the hoop is the only force which is computed by:F net = 2.8kg*9.81m/s^2 = 27.468 N 
the slow masses that must be quicker are the pulley, ring, and the rolling sphere. 
The mass correspondent of M the pulley is computed by torque τ = F*R = I*α = I*a/R F = M*a = I*a/R^2 --> M = I/R^2 = 21/2*m*R^2/R^2 = 1/2*m 
The mass equal of the rolling sphere is computed by: the sphere revolves around the contact point with the table. So using the proposition of parallel axes, the moment of inertia of the sphere is I = 2/5*mR^2 for spin about the midpoint of mass + mR^2 for the distance of the axis of rotation from the center of mass of the sphere. I = 7/5*mR^2 M = 7/5*m 
the acceleration is then a = F/m = 27.468/(2.8 + 1/2*2 + 7/5*4) = 27.468/9.4 = 2.922 m/s^2
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Answer:

Velocity, v = 0.164 m/s

Explanation:

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Wavelength, \lambda=4.1\ m

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v=f\lambda\\\\v=0.04\times 4.1\\\\v=0.164\ m/s

So, the velocity of a water wave is 0.164 m/s.

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3 years ago
A gyroscope flywheel of radius 1.96 cm is accelerated from rest at 13.0 rad/s2 until its angular speed is 2270 rev/min. (a) What
nika2105 [10]

Tangential acceleration of a point on the rim of the flywheel during this spin-up process is 0.2548 m/s².

Tangential acceleration is defined as the rate of change of tangential velocity of the matter in the circular path.

Given,

Radius of flywheel (r) = 1.96 cm = 0.0196m

Angular acceleration (α)= 13.0 rad/s²

The tangential acceleration formula is at=rα

where, α is the angular acceleration, and r is the radius of the circle.

using the formula; at=rα  = (13.0 rad/s²) (0.0196m) = 0.2548 m/s².

The tangential acceleration is 0.2548 m/s².

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1 year ago
Isla made a diagram to compare X-rays and radio waves.
pickupchik [31]

A: Has a higher frequency --> X-rays

B: Travels at the same speed --> Both

C: Has a longer wavelength --> Radio waves

Explanation:

Electromagnetic waves are waves consisting of oscillations of electric and magnetic field in a direction perpendicular to the direction of motion of the wave.

Electromagnetic waves travel at the speed of light (c=3.0\cdot 10^8 m/s) in a vacuum, and they are transverse in nature (the direction of vibration is perpendicular to the direction of propagation).

Electromagnetic waves are classified into different types according to their wavelength and frequency. In order from shortest to longest wavelength (and so, from highest to lowest frequency, since frequency is inversely proportional to the wavelength), we have:

Gamma rays

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Microwaves

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Therefore, we can no says that:

X-rays: has a higher frequency than Radio waves

Radio waves: have a longer wavelength than x-rays

Both: they travel at the same speed

Therefore, the correct pairing is:

A: Has a higher frequency --> X-rays

B: Travels at the same speed --> Both

C: Has a longer wavelength --> Radio waves

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6 0
3 years ago
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scoundrel [369]

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Putting values,

F= mv²/r = 0.5× 3²/0.5 = 9 N

7 0
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Answer:

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Explanation:

that is my own thinking

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