The equilibrium temperature is T13=3.12 ◦C
<u>Explanation:</u>
<u>Given </u>
The temperature of liquids: T1=6◦C, T2=23◦C, T3=38◦C
The temperature of 1+2 liquids mix: T12= 13◦C.
The temperature of 2+3 liquids mix: T23=26.8 ◦C.
The temperature of 1+3 liquids mix: T13= ??
<u>1.When the first two liquids are mixed:</u>
- mC1(T1-T12)+mC2(T2-T12)=0
- C1(6-13)=C2(23-13)=0
- 7C1=10C2
- C1=1.42C2
<u>2.When the second and third liquids are mixed</u><u>:</u>
- mC2(T2-T23)+mC3(T3-T23)=0
- C2(23-26.8)=C3(38-26.8)=0
- 3.8C2=12.8C3
- C2=3.36C3
<u>3.When the first and third liquids are mixed:</u>
- mC1(T1-T13)+mC3(T3-T13)=0
- C1(6-T13)+C3(38-T13)=0
- C1=1.42C2 C2=3.36C3
- C1=1.42C2(3.36C3)
- C1=4.77C3
- C1(6-T13)+C3(38-T13)=0
- 4.77C3(6-T13)+C3(38-T13)=0
- By solving the equation we get,
- T13=3.12 ◦C
- The equilibrium temperature is T13=3.12 ◦C
<u></u>
Answer:
Momentum of bullet
momentum of baseball
Explanation:
As we know that momentum is defined as the product of mass and velocity
here we know that
mass of the bullet = 8 gram
velocity of bullet = 340 m/s
momentum of the bullet is given as
Now we have
mass of baseball = 0.2 kg
velocity of baseball = 40 m/s[/tex]
momentum of baseball is given as
On question 30, that is a displacement- time graph (DT). On this type of graph the gradient is equal to the velocity. B has the steepest gradient, then A and finally C
Now velocity is a vector quantity so it has a direction and speed ( speed doesn't have a fixed direction.)
on the DT graph im going to assume that movement B is a positive velocity with A and C being negative.
So by ranking these: A is the most negative, C is the least negative and B has to be the greatest as it is the only positive velocity.
Q31, The same type of graph is present, by looking at the gradients we can rank the largest and smallest velocities- speeds in the case of the question.
i'll skip my working out as its the same as before:
C, B, A and then D
the same idea as on Q30 applies to Q31 part b,
D,C,B then A
