Answer:
Correct: B
Explanation:
The first block wont move because:
Σf=3-3=0N.
The second block will move because:
Σf:5-3=2N (direction to the right).
The third block will move because:
Σf=3N (direction to the right).
<h3>
Answer:</h3>
4.56 × 10^-19 Joules
<h3>
Explanation:</h3>
We are given;
- Wavelength of the wave as 435.8 nm
We are required to calculate the amount of energy released by an electron.
- We know that the speed of the wave, c is 2.998 × 10^8 m/s
- But, c = f × λ , where f is the frequency and λ is the wavelength
- Energy of a wave is given by the formula;
E = hf , where h is the plank's constant, 6.626 × 10^-34 J-s
But, f = c/λ
Therefore;
f = (2.998 × 10^8 m/s) ÷ (4.358 × 10^-7 m)
= 6.879 × 10^14 Hz
Thus;
Energy = 6.626 × 10^-34 J-s ×6.879 × 10^14 Hz
= 4.558 × 10^-19 Joules
= 4.56 × 10^-19 Joules
Therefore, the energy that must be released by the electron is 4.56 × 10^-19 Joules
You have to use the equation q=mcΔT and solve for T(final).
T(final)=(q/mc)+T(initial)
q=the amount of energy absorbed or released (in this case 868J)
m=the mass of the sample (in this case 15.6g)
c= the specific heat capacity of the substance (in this case 2.41 J/g°C)
T(initial)=the initial temperature of the sample (in this case 21.5°C)
When you plug everything in, you should get 44.6°C.
Therefore the final temperature of ethanol is 44.6°C
I hope this helps. Let me know if anything is unclear.
Answer:
2Al(s) + 6HCl(aq) = 2AlCl3(aq) + 3H2(g)
Explanation:
The reaction is a displacement reaction.
The reaction does not commence immediately because the Al(aluminum) has Al2O3 (Aluminum oxide) which protect it from reacting with water.
It takes some time for the HCl (hydrochloric acid) to eat the coating, then the reaction proceed vigorously to produce hydrogen gas bubbles. Generally metals that are above hydrogen in the electrochemical series tend to displace Hydrogen from Hydrochloric acid. The more negative the electrochemical volts the more the tendency to lose electron. Metal above hydrogen have negative evolts while those below have positive evolts
Answer:
<em><u>PLZ</u></em><em><u> </u></em><em><u>MARK</u></em><em><u> </u></em><em><u>ME</u></em><em><u> </u></em><em><u>BRIANLIEST</u></em><em><u> </u></em><em><u>I</u></em><em><u> </u></em><em><u>REALLY</u></em><em><u> </u></em><em><u>WANT</u></em><em><u> </u></em><em><u>IT</u></em><em><u> </u></em><em><u>PLZZZZZZ</u></em><em><u> </u></em><em><u>ISS</u></em><em><u> </u></em><em><u>GARIB</u></em><em><u> </u></em><em><u>KI</u></em><em><u> </u></em><em><u>DUA</u></em><em><u> </u></em><em><u>LAGEGI</u></em><em><u> </u></em><em><u>YARR</u></em><em><u> </u></em><em><u>PLZ</u></em>
Explanation:
<em>Glucose and galactose are monosaccharides that differ from one another only at position C-4. Thus, they are epimers that have an identical configuration in all the positions except in position C-4. ... Glucose and galactose are epimers that do not differ in position C-5 but differ in position C-4.</em>