Answer:
The final temperature of water = 22.1224 °C
Explanation:
<u>Step 1</u> : defien the formula for heat transfer
q = m*c*ΔT
with q = heat transfer
with m = mass of the substance
with c = specific heat ( of water in this case)
with ΔT = difference between final temperature and initial temperature
In this case :
q=366kJ = 366 *10^3 J
mass of water = 48kg = 48000g
c= specific heat of wwater = 4.184 J / g °C
initial temperature = 20.3 °C
final temperature = TO BE DETERMINED
<u>Step 2</u>: Calculate temperature
366000 J = 48000g * 4.184J/g °C * (T2 - 20.3)
366000 / (480000 * 4.184) = 1.8224 = (T2 - 20.3)
T2 = 20.3 + 1.82 =22.1224 ° C
The final temperature of water = 22.1224 °C
Explanation:
B more negative charges than positive charges
Answer:
Chemotherapy drugs and other toxins are actively pumped out of cancer cells by transmembrane proteins.
Explanation:
Drugs inside the cell can be inactivated by oxidation and / or conjugation with glutathione, such as glutathione S-transferases, playing an important role in detoxification. However, conjugation is not enough for drug elimination. And this is where the GS-X pumps appear. Transporter proteins, such as Mrp protein, act as GS-X pumps. The PgP, Mrp and Bcrp proteins function as expulsion pumps, thus reducing the intracellular accumulation of drugs, causing resistance in cancer cells.
<u>Answer:</u> The mass of iron (III) nitrate is 11.16 g/mol
<u>Explanation:</u>
To calculate the mass of solute, we use the equation used to calculate the molarity of solution:
We are given:
Molarity of solution = 0.3556 M
Molar mass of Iron (III) nitrate = 241.86 g/mol
Volume of solution = 129.8 mL
Putting values in above equation, we get:
Hence, the mass of iron (III) nitrate is 11.16 g/mol
