Here is your answer !!! Last day we have solve this question and the answer is easy to get in mind
Of course, you can ask science questions under biology or another subject.
The prediction of the products and the balanced form of the above incomplete equation is as follows: Ag + Cu(NO3)2 → Cu + Ag(NO3)2 (option D).
<h3>How to balance a chemical reaction?</h3>
According to this question, silver reacts with copper nitrate to form products that were not stated.
However, this reaction is an example of a displacement reaction, hence, silver will displace or replace copper in the compound to form copper and silver nitrate as products. The reaction is given as follows:
Ag + Cu(NO3)2 → Cu + Ag(NO3)2
This chemical reaction is said to be balanced because the number of moles of each atoms on both sides of the equation is the same.
Learn more about balanced equation at: brainly.com/question/7181548
#SPJ1
The question provides the data in an incorrect way, but what the question is asking is for the entropy change when combining 3 moles of water at 0 °C (273.15 K) with 1 mole of water at 100 °C (373.15 K). We are told the molar heat capacity is 75.3 J/Kmol. We will be using the following formula to calculate the entropy change of each portion of water:
ΔS = nCln(T₂/T₁)
n = number of moles
C = molar heat capacity
T₂ = final temperature
T₁ = initial temperature
We can first find the equilibrium temperature of the mixture which will be the value of T₂ in each case:
[(3 moles)(273.15 K) + (1 mole)(373.15 K)]/(4 moles) = 298.15 K
Now we can find the change in entropy for the 3 moles of water heating up to 298.15 K and the 1 mole of water cooling down to 298.15 K:
ΔS = (3 moles)(75.3 J/Kmol)ln(298.15/273.15)
ΔS = 19.8 J/K
ΔS = (1 mole)(75.3 J/Kmol)ln(298.15/373.15)
ΔS = -16.9 J/K
Now we combine the entropy change of each portion of water to get the total entropy change for the system:
ΔS = 19.8 J/K + (-16.9 J/K)
ΔS = 2.9 J/K
The entropy change for combining the two temperatures of water is 2.9 J/K.
Answer:
0.01 mol of H+.
Explanation:
Equation of reaction:
Mg(s) + 2HCl(aq) --> MgCl2(aq) + H2(g)
Molar concentration = number of moles/volume
= 1*0.01
= 0.01 mol.
Dissociation:
2HCl --> 2H+ + 2Cl-
By stoichiometry,
If 2 mole of HCl dissociates to guve 2 moles of H+
Number of moles of H+ = 0.01 mol.
