What number completes the missing part of this nuclear equation?:
2 answers:
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An Arrhenius base is a molecule that when dissolved in water will break down to yield an or hydroxide ion in solution.
An Arrhenius base is a compound that increases the ion concentration in aqueous solution.
An Arrhenius base is a substance that, when dissolved in an aqueous solution, increases the concentration of hydroxide, or , ions in the solution.
Bases Properties
Arrhenius bases that are soluble in water can conduct electricity.
Bases often have a bitter taste and are found in foods less frequently than acids. Many bases, like soaps, are slippery to the touch.
Bases also change the colour of indicators. Red litmus turns blue in the presence of a base (see figure below), while phenolphthalein turns pink.
Some bases react with metals to produce hydrogen gas.
Acids (pH < 7.0) react with bases (pH > 7.0) to produce a salt and water. When equal moles of an acid and a base are combined, the acid is neutralized by the base. The resulting mixture will have a more neutral pH.
An Arrhenius acid is a substance that dissociates in water to form hydrogen ions or protons. In other words, it increases the number of ions in the water. In contrast, an Arrhenius base dissociates in water to form hydroxide ions
.
Example, sodium hydroxide, is added to an aqueous solution. NaOH dissociates into sodium, , and hydroxide,
ions.
Learn more about the Arrhenius bases here:
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Answer:
The option closest to the percentage yield is option;
d. 81.1
Explanation:
The given chemical equation of the reaction is presented as follows;
CaO (s) + H₂O (l) → Ca(OH)₂
The mass of CaO in the experiment, m = 2.00 g
The volume of water with which the CaO was reacted = Excess volume of water
Number of moles = Mass/(Molar mass)
The mass of Ca(OH)₂ recovered, actual yield = 2.14 g
The molar mass of CaO = 56.0774 g/mol
The number of moles of CaO in the reaction, n₁ = 2.00 g/(56.0774 g/mol ≈ 0.036 moles
The molar mass of Ca(OH)₂ = 74.093 g/mol
The number of moles of Ca(OH)₂ in the reaction, n₂ = 2.14 g/(74.093 g/mol) ≈ 0.029 moles
From the given chemical reaction, one mole of CaO reacts with one mole of H₂O to produce one mole of Ca(OH)₂
Therefore, 0.036 moles of CaO will produce 0.036 moles of Ca(OH)₂
Mass = Number of moles × Molar mass
The mass of 0.036 moles of Ca(OH)₂ ≈ 0.036 moles × 74.093 g/mol = 2.667348 grams
∴ The theoretical yield of Ca(OH)₂ = 2.667348 grams
The percentage yield = (2.14 g)/(2.667348 grams) × 100 = 80.23%
Therefore, the option which is closest is option d. 81.1.