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DochEvi [55]
3 years ago
10

-K+ _ MgBr → _KBr + __Mg

Mathematics
1 answer:
Anit [1.1K]3 years ago
7 0

Answer:K + MgBr → KBr + Mg

This is an oxidation-reduction (redox) reaction:

MgI + e- → Mg0

(reduction)

K0 - 1 e- → KI

(oxidation)

MgBr is an oxidizing agent, K is a reducing agent.

Step-by-step explanation:

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Answer:

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Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

<u>Solution:</u>

We have been given a cubic polynomial.

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Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

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we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

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Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}

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\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}

And,

\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0
3 years ago
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dimaraw [331]
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