Let, the height of the building be x ft.
Given the building casts 35ft shadow.
The height of the flagpole given which is 22ft and casts a shadow of 10ft.
Now to find the height of the building we have to equate the ratio of height and shadow of the building and the flagpole.
So we can write,
x/35 = 22/10
To find x, we have to get rid of 35 from the left side and have to move it to right side. As 35 is divided there, we will multiply 35 to both sides.
(x/35)× 35 = (22/10)×35
x = (22×35)/10
x = 770/10
x = 77
So, the height of the building is 77 ft which is the required answer here.
Answer:
CE = 17
Step-by-step explanation:
∵ m∠D = 90
∵ DK ⊥ CE
∴ m∠KDE = m∠KCD⇒Complement angles to angle CDK
In the two Δ KDE and KCD:
∵ m∠KDE = m∠KCD
∵ m∠DKE = m∠CKD
∵ DK is a common side
∴ Δ KDE is similar to ΔKCD
∴ 
∵ DE : CD = 5 : 3
∴ 
∴ KD = 5/3 KC
∵ KE = KC + 8
∵ 
∴ 
∴ 
∴ 
∴ 
∴ KC = (8 × 9) ÷ 16 = 4.5
∴ KE = 8 + 4.5 = 12.5
∴ CE = 12.5 + 4.5 = 17
Answer:
8^ (1/3) =2
Step-by-step explanation:
We want to find cube root of 8
8^ (1/3)
What number times itself 3 times is 8
2*2*2 =8
8^ (1/3) =2
Answer:5√(3)z^9
Step-by-step explanation:
Square root of 75z^18
√(75z^18)
√(75) x √(z^18)
√(25x3) x (z^18)^(1/2)
√(25) x √(3) x z^(18x1/2)
5 x √(3) x z^9
5√(3)z^9
Step-by-step explanation:
Adding 10 to both sides of the original equation gets us q = 6(r + 1) + 10. Since q is equal to h(r), we get h(r) = 6(r + 1) + 10 = 6r + 16.