All categories

3 years ago

Angle 1 and Angle 2 are supplementary. The measure of Angle 2 is 78

Mathematics

1 answer:

N76 [4]3 years ago

5 0

Answer: Angle 1 is 129 degrees. Angle 2 is 51 degrees.

Step-by-step explanation: 129+51=180 129-51=78

You might be interested in

Complete the factoring,<br> 5x^2 - 40x = 5x( ) <br><br> HELP ASAP PLS!

Aleksandr-060686 [28]

Answer:

$5x(x-8)$

Step-by-step explanation:

Factor $5x$ out of $5x^{2} -40x$

8 0

2 years ago

Jimmy has a piece of string that is 6 3/4 inches long, and Sam has a piece of string that is 7 1/2 inches long.

mafiozo [28]

Answer:

3/4 inches

Step-by-step explanation:

Subtract Jimmys string length from Sam's string length

7 1/2 - 6 3/4

Get a common denominator of 4

7 1/2*2/2 - 6 3/4

7 2/4 - 6 3/4

Borrow 1 ( or 4/4) from the 7

6 4/4 + 2/4 - 6 3/4

6 6/4 - 6 3/4

3/4

6 0

2 years ago

Read 2 more answers

He completed 2 and 4/5 rows of grapes each hour he worked after completing 140 rows of grapes how many hours had he worked?

algol [13]

Step-by-step explanation:

Divide 140 by $2\frac{4}{5}$ to represent the amount of hours he worked.

To make dividing easier, $2\frac{4}{5}$ can also represent 2.8 as a decimal.

$\frac{140}{2.8} =50$

He has worked 50 hours after completing 140 rows of grapes.

4 0

2 years ago

How many degrees is Arc DC

kkurt [141]

Answer:13

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)

viktelen [127]

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}$

The first line segment can be parameterized by $\mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle$ with $0\le t\le1$ . Denote this first segment by $C_1$ . Then

$\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt$
$=108$

The second line segment ( $C_2$ ) can be described by $\mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle$ , again with $0\le t\le1$ . Then

$\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt$
$=-\dfrac{229}3$

Finally,

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3$

5 0

3 years ago