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mash [69]
4 years ago
11

determine the percent yield of copper by dividing the actual yield (in moles) by the theoretical yield (in moles). percent yield

= %
Physics
1 answer:
Elden [556K]4 years ago
3 0

Answer:

79% is = to the percent yield

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body starting from rest and moving with an uniform acceleration of 3 m/s²..What is its velocity after 15s?​
Luba_88 [7]
<h2>Answer :</h2>

□ The Final velocity of body = 45 m/s\sf{ }

<h2>Given :</h2>

Initial velocity of body = 0 m/s

Acceleration of body = 3 m/s²

Time taken by body = 15 sec

<h2>To Calculate :</h2>

Final velocity of body = ?

<h2>How To Calculate ?</h2>

<h3>❒ </h3>

Here in this question we are provided that a body is in rest so it's initial velocity will be 0 m/s (because from rest), Acceleration of body is 3 m/s², and Time taken is also given which is 15 sec.

<h3>❒</h3>

 To calculate the Final velocity of body we'll use the first equation of motion which says v = u + at

Where,

  • v is the Final velocity in m/s.

  • u is the Initial velocity in m/s.

  • a is the Acceleration in m/s².

  • t is the Time taken in second.

<h2>Calculation :</h2>

From first equation of motion

  • ⇒ v = u + at

  • ⇒ v = 0 + 3 × 15

  • ⇒ v = 0 + 45

  • ⇒ v = 45

Hence, the Final velocity of body is 45 m/s.

7 0
3 years ago
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A gas is confined in a cylinder with a piston. What happens when work is done on the gas.
goblinko [34]
It combusts in to a vapor

5 0
3 years ago
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A car is traveling with a velocity of 40 m/s and has a mass of 1120 kg. What is the KE of the car?
anygoal [31]

Therefore, the kinetic energy of the car is 896,000 J.

4 0
3 years ago
What do all heterotrophs have in common?
ss7ja [257]

Answer:

c

Explanation:

your welcome dude good luck

6 0
3 years ago
The Hubble Space Telescope orbits the Earth at approximately 612,000m altitude. Its mass is 11,100 kg and the mass of earth is 5
nexus9112 [7]

Answer:

7.55 km/s

Explanation:

The force of gravity between the Earth and the Hubble Telescope corresponds to the centripetal force that keeps the telescope in uniform circular motion around the Earth:

G\frac{mM}{R^2}=m\frac{v^2}{R}

where

G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2} is the gravitational constant

m=11,100 kg is the mass of the telescope

M=5.97\cdot 10^{24} kg is the mass of the Earth

R=r+h=6.38\cdot 10^6 m+612,000 m=6.99\cdot 10^6 m is the distance between the telescope and the Earth's centre (given by the sum of the Earth's radius, r, and the telescope altitude, h)

v = ? is the orbital velocity of the Hubble telescope

Re-arranging the equation and substituting numbers, we find the orbital velocity:

v=\sqrt{\frac{GM}{R}}=\sqrt{\frac{(6.67\cdot 10^{-11})(5.97\cdot 10^{24} kg)}{6.99\cdot 10^6 m}}=7548 m/s=7.55 km/s

6 0
3 years ago
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