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inn [45]
3 years ago
14

Landon attends an early childhood program that is located at a community center which also runs an adult care program.

Physics
1 answer:
Ira Lisetskai [31]3 years ago
3 0
Good for Landon. What’s the question?
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How much work can a 22kw car engine do in 60 seconds
Sindrei [870]

Answer:

13.2 x 10^5 J

Explanation:

Power = work/time

Given

Power = 22kw

= 22 x 1000 = 22000w

Time = 60 secs

Therefore

22000 = work/60

Cross multiply

Work = 22000 x 60

= 1320000

= 13.2 x 10^5J

6 0
3 years ago
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Mrs. Walker has on new shoes! When she walks down the waxed hall floors she slips and slides. What could Mrs. Walker do to help
givi [52]
She could choose to wear shoes designed to have more friction on the bottom, so she won’t slip as easily... (or she could get like a walker or something to hold onto if she really wanted to show off her new shoes)
Hope this helps x
3 0
3 years ago
Give two example of Pseudoscience?
Bingel [31]

Answer:

1. astrology

2. crystology

Explanation:

please mark me as branliest

4 0
3 years ago
The chemical equation below shows the reaction of methane (CH4) and oxygen gas (O2) to form carbon dioxide (CO2) and water (H2O)
Nuetrik [128]
<h2>Answer </h2>

Option C - Carbon Dioxide and Water

<u>Explanation </u>

The chemical equation reaction of methane (CH4) and oxygen gas (O2) to form carbon dioxide (CO2) and water (H2O).

CH4 + 2O2 → CO2 + 2H2O.

In this equation, carbon dioxide and water are products. Products are substances which are formed after a chemical reaction so in this case carbon dioxide and water are formed as a result after a chemical reaction. Therefore, these are products of reaction of methane and oxygen gas.

8 0
3 years ago
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What height will the object reach? 12 points. Will give brainliest.
umka21 [38]

Answer:

12.7 m

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 56.7 Km/hr

Maximum height (h) =..?

First, we shall convert 56.7 Km/hr to m/s. This can be obtained as follow:

Initial velocity (m/s) = 56.7 x 1000/3600

Initial velocity (m/s) = 15.75 m/s

Next, we shall determine the time taken to get to the maximum height. This can be obtained as follow:

Initial velocity (u) = 15.75 m/s

Final velocity (v) = 0 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

v = u – gt (since the ball is going against gravity)

0 = 15.75 – 9.8 × t

Rearrange

9.8 × t = 15.75

Divide both side by 9.8

t = 15.75/9.8

t = 1.61 secs.

Finally, we shall determine the maximum height as follow

h = ½gt²

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) = 1.61 secs.

Height (h) =..?

h = ½gt²

h = ½ × 9.8 × 1.61²

h = 4.9 x 1.61²

h = 12.7 m

Therefore, the maximum height reached by the ball is 12.7 m

3 0
3 years ago
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