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mars1129 [50]
3 years ago
15

What structure is located at the front edge of the retina and has a tooth like appearance?

Physics
1 answer:
pogonyaev3 years ago
3 0

Ora serrate is located at the front edge of the retina and has a tooth like appearance.

Our eye has many portions and parts, all of them are there for some function. The ora serrata is the most anterior extent of the retina or serrated junction between the retina and the ciliary body. The retina ends at the ora serrata, where the ciliary body begins.

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If two normal distributions each have the same mean, but one has a standard deviation of 1 and the other has a standard deviatio
likoan [24]

In comparison to a distribution with a standard deviation of 5, one has a curve with a higher peak. The variability will be greater the larger the standard deviation. It denotes increased variability in a distribution with a standard deviation of 5.

<h3>What do you mean by the term standard deviation?</h3>

The term "standard deviation" (or "") refers to a measurement of the data's dispersion from the mean. A low standard deviation implies that the data are grouped around the mean, whereas a large standard deviation shows that the data are more dispersed. In contrast, a high or low standard deviation indicates that the data points are, respectively, above or below the mean. A standard deviation that is close to zero implies that the data points are close to the mean. the curve at the top is more dispersed and has a greater standard deviation than the curve at the bottom, which is more concentrated around the mean and has a lower standard deviation.

To learn more about standard deviation, Visit:

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8 0
1 year ago
Consider 2 converging lenses of focal lengths 5 mm (objective) and 50 mm.(eyepiece) An object 0.1 mm in size is placed a distanc
AleksandrR [38]

Answer:

1)   q₁ = 12.987 cm , b)       L = 17.987 cm , c)      m = 179.87

Explanation:

We can solve the geometric optics exercises with the equation of the constructor

         1 / f = 1 / p + 1 / q

where f is the focal length, p and q are the distance to the object and the image respectively.

Let's apply this equation to our case

1) f = 5mm = 0.5 cm

    p₁ = 5.2 mm = 0.52 cm

    h = 0.1 mm = 0.01 cm

    1 / q₁ = 1 / f- 1 / p

    1 / q₁ = 1 / 0.5 - 1 / 0.52 = 2 - 1.923

    1 / q₁ = 0.077

    q₁ = 12.987 cm

2) in this part they tell us that the eyepiece creates an image at infinity, therefore the object that comes from being at the focal length of the eyepiece

            p₂ = 5 cm

The absolute thing that goes through the two lenses is

           L = q₁ + p₂

           L = 12.987 +5

           L = 17.987 cm

3) This lens configuration forms the so-called microscope, whose expression for the magnifications

           m = -L / f_target 25 cm / f_ocular

           m = - 17.987 / 0.5 25 / 5.0

            m = 179.87

8 0
3 years ago
Help me and get points..
Rufina [12.5K]

Answer:

B) Depends on launch speed.

Explanation:

This is true when considering the basketball player in a given basketball game. The speed at which the player jumps up is a strong factor which determines the acceleration of his acceleration. The direct co-relation show that, speed and acceleration of the basketball player are interrelated.

4 0
2 years ago
Electromagnetic waves can transfer energy without which of the following?
Ugo [173]
The correct answer is A. Electromagnetic waves can transfer energy without a medium. Heat can be transferred through a vacuum only via radiation. Infrared waves are electromagnetic waves that does not require a medium to travel. Heat is transferred in a vacuum in the form of infrared waves.
7 0
2 years ago
Read 2 more answers
a 2.9-cm-diameter parallel-plate capacitor has a 2.0 mm spacing. the electric field strength inside the capacitor is
Elenna [48]
The electric field strength between the plates is<br /><br />(voltage between the plates) / (0.002) <br /><br />volts per meter.
5 0
3 years ago
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