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olchik [2.2K]
3 years ago
15

The special relationship between the ohm, the ampere, and the volt can be expressed using what?​

Physics
1 answer:
german3 years ago
8 0

Answer:

Ohm's law: I = V / R

Explanation:

V, I, and R, the parameters of Ohm's law

with

V = voltage in Volt

I = current in Ampere

R = resistance in Ohm

Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points. Introducing the constant of proportionality.

The following equation is known as Ohm's law:

I = V / R

You can also write Ohm's law as

V = I * R

You can also write Ohm's law as

R = V / I

Ohm's law states that the R in this relation is constant, independent of the current

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4 0
3 years ago
Given that the concentration of bovine carbonic anhydrase is 3.3 pmol ⋅ L − 1 and R max ( V max ) = 222 μmol ⋅ L − 1 ⋅ s − 1 , d
LuckyWell [14K]

Answer:

The turnover number of the enzyme molecule bovine carbonic anhydrase = 67,272,727.27 s^–1.

Explanation:

Given:

The concentration of bovine carbonic anhydrase = total enzyme concentration = Et = 3.3 pmol⋅L^–1 = 3.3 × 10^–12 mol.L^–1

The maximum rate of reaction = Rmax (Vmax) = 222 μmol⋅L^–1⋅s^–1 = 222 × 10^–6 mol.L^–1⋅s^–1

The formula for the turnover number of an enzyme (kcat, or catalytic rate constant) = Rmax ÷ Et = 222 × 10^–6 mol.L^–1⋅s^–1 ÷ 3.3 × 10^–12 mol.L^–1 = 67,272,727.27 s^–1

Therefore, the turnover number of the enzyme molecule bovine carbonic anhydrase = 67,272,727.27 s^–1

3 0
4 years ago
Which of the following BEST describes what occurs in a fusion reaction?
Greeley [361]

Answer:

Two mass nuclei are joined to form one nucleus

Explanation:

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4 0
3 years ago
A vertical spring with stiffness k originally is at rest with no mass attached. Then, a mass M is attached, and the spring rocks
Alina [70]

Answer:

The position of the spring in terms of g, m & k is x = \frac{m g}{k}

Explanation:

Stiffness of the spring = k

Mass = m

When a mass m is attached with the spring then spring stretched. in that case the force exerted on the spring is equal to weight of the mass attached.

⇒ Force exerted on the spring F = k x

⇒ m g = k x

⇒ x = \frac{m g}{k}

This is the position of the spring in terms of g, m & k.

8 0
4 years ago
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