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grandymaker [24]
3 years ago
8

What is pressure?

Physics
2 answers:
Alenkasestr [34]3 years ago
8 0
C. The force exerted on a given area.
viva [34]3 years ago
3 0

Answer:

i think C

Explanation:

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A loop of wire is placed in a uniform magnetic field. (a) For what orientation of the loop is the magnetic flux a maximum? The p
ra1l [238]

Answer:

1) The plane of the loop is perpendicular to the magnetic field.

2) The magnetic flux is independent of the orientation of the loop.p

Explanation:

The flux is calculated as φ=BAcosθ. The flux is therefore the highest when the magnetic field vector is perpendicular to the plane of the loop We can also deduce that the flux is zero when there is no magnetic field part perpendicular to the loop When the angle reaches zero, the flux is in the limit because when the angle becomes zero, the cos is the maximum.

5 0
3 years ago
Find the Acceleration of a car with the mass of 1200kg and a force of 11x10^3 N
larisa86 [58]

Answer:

<h2>9.17 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{11 \times  {10}^{3} }{1200}  \\  = 9.16666...

We have the final answer as

<h3>9.17 m/s²</h3>

Hope this helps you

7 0
2 years ago
A plastic ball of mass 0.200 kg moves with a velocity of 0.30 m/s. This plastic ball collides with a second plastic ball of mass
GrogVix [38]
<h2>Velocity of 0.2 kg ball is 0.17 m/s</h2>

Explanation:

Let the mass of balls be m and M.

Initial velocity ball 1 be u₁, ball 2 be u₂

Final velocity ball 1 be v₁, ball 2 be v₂

Initial momentum = m x u₁ + M x u₂ = 0.2 x 0.3 + 0.1 x 0.1 = 0.07 kgm/s

Final momentum = m x v₁ + M x v₂ = 0.2 x v₁ + 0.1 x 0.36 = 0.2v₁ + 0.036

We have momentum conservation

Initial momentum = Final momentum

0.07 = 0.2v₁ + 0.036

v₁ = 0.17 m/s

Velocity of 0.2 kg ball is 0.17 m/s

8 0
3 years ago
Air enters an adiabatic compressor at 104 kPa and 292 K and exits at a temperature of 565 K. Determine the power (kW) for the co
ladessa [460]

Answer:

\dot W_{in} = 49.386\,kW

Explanation:

An adiabatic compressor is modelled as follows by using the First Law of Thermodynamics:

\dot W_{in} + \dot m \cdot c_{p}\cdot (T_{1}-T_{2}) = 0

The power consumed by the compressor can be calculated by the following expression:

\dot W_{in} = \dot m \cdot c_{v}\cdot (T_{2}-T_{1})

Let consider that air behaves ideally. The density of air at inlet is:

P\cdot V = n\cdot R_{u}\cdot T

P\cdot V = \frac{m}{M}\cdot R_{u}\cdot T

\rho = \frac{P\cdot M}{R_{u}\cdot T}

\rho = \frac{(104\,kPa)\cdot (28.02\,\frac{kg}{kmol})}{(8.315\,\frac{kPa\cdot m^{3}}{kmol\cdot K} )\cdot (292\,K)}

\rho = 1.2\,\frac{kg}{m^{3}}

The mass flow through compressor is:

\dot m = \rho \cdot \dot V

\dot m = (1.2\,\frac{kg}{m^{3}})\cdot (0.15\,\frac{m^{3}}{s} )

\dot m = 0.18\,\frac{kg}{s}

The work input is:

\dot W_{in} = (0.18\,\frac{kg}{s} )\cdot (1.005\,\frac{kJ}{kg\cdot K})\cdot (565\,K-292\,K)

\dot W_{in} = 49.386\,kW

5 0
2 years ago
A chemical reaction is the only way to an
Klio2033 [76]

Answer:

B: Pure Substance

Explanation:

7 0
2 years ago
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