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nydimaria [60]
3 years ago
13

How does the size of a bar magnet's magnetic field compare to that of Earth's? A. A bar magnet's magnetic field is larger than E

arth's. B. A bar magnet's magnetic field is smaller than Earth's. C. A bar magnet's magnetic field is the same size as Earth's.
Mathematics
1 answer:
inn [45]3 years ago
7 0

Answer:

A. A bar magnet’s magnetic field is larger than Earth’s.

Step-by-step explanation:

The average magnetic field strength in the Earth's outer core was measured to be 25 Gauss, 50 times stronger than the magnetic field at the surface.

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The Frostburg-Truth bus travels on a straight road from Frostburg Mall to Sojourner Truth Park. The mall is 3 miles west and 2 m
Verizon [17]
To start, write your locations as points, with north and south being positive and negative y respectively and east and west being positive and negative x respectively. Doing this gives us the mall at (-3,-2) and the park at (4,5). Now, we use our distance formula ( \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 } ) to solve for the unknown distance. Plugging in with the park values as our second values and our mall values as our first values (as well as with our unknown distance as d), we get d= \sqrt{(4-(-3))^2+(5-(-2))^2} = \sqrt{(7)^2+(7)^2} = \sqrt{49+49} = \sqrt{98}. This square root can be rounded to 9.9 miles.
4 0
3 years ago
Suppose xy=−4 and dy/dt=−3. Find dx/dt when x=−1.
user100 [1]
When x=-1: \quad (-1)y=-4\qquad\to\qquad y=4\)

Ok that gives us a little more information.
If we implicitly differentiate with respect to t, from the very start, then we can apply our product rule, ya?

x'y+xy'=0

The right side is zero, derivative of a constant is zero.
Where x' is dx/dt and y' is dy/dt.

From here, plug in all the stuff you know:
y' = -3
x = -1
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and solve for x'.

Hope that helps!
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3 years ago
Order the values from least to greatest.
Soloha48 [4]
The answer is c have a good day
8 0
2 years ago
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Carson evaluated 23÷34 and got an answer of 89. Which statement is true about his answer?
Tomtit [17]
23÷34 = 0.6764705882352941. totally answer

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3 years ago
Find the number of real number solutions for the equation. x^2+5x+7=0
koban [17]

Given a quadratic equation ax^2+bx+c=0, we define the discriminant as

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The number of real solutions of the equation depend on the sign of \Delta:

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In this case, we have

\Delta = 25-28=-3

And so this equation has no real solutions.

7 0
3 years ago
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