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noname [10]
3 years ago
5

Non-ferrous alloys do not contain a. copper. b. brass. c. gold. d. iron.

Chemistry
2 answers:
podryga [215]3 years ago
6 0
D: Iron

Ferrous roughly means "to contain iron", so if something is non-ferrous,it does not contain iron.

(Extra knowledge: The Latin for Iron is "Ferrum", which is why we say "ferrous" and why the periodic symbol for Iron is Fe!)
Elena L [17]3 years ago
4 0
Iron is the correct answer
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The  volume  occupied  by 2.00  moles of nitrogen  gas at  the same  temperature  and pressure  will be

 0.500  moles = 11.2 Liters
 what about 2 moles =? liters

by cross  multiplication

= 11.2 liters  x   2moles/ 0.500 moles  =  44.8  liters 
8 0
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Which class of biomolecule do the molecules in the table belong to?
kondaur [170]
The oythagorean theroem
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3 years ago
As changes in energy levels of electrons increase, the frequencies of atomic line spectra they emit ___?
Tju [1.3M]

Ans: As changes in energy levels of electrons increase, the frequencies of atomic line spectra they emit will <u>increase.</u>

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E = hν

where h = planck's constant

The change in energy i between levels is:

ΔΕ = h(Δν)  -----(1)

Based on the above equation, as the changes in energy levels increase, the frequency of emitted radiation will also increase.



6 0
3 years ago
For the titration of 25.00 mL of 0.150 M HCl with 0.250 M NaOH, calculate:
Leviafan [203]
1) Chemical reaction

HCl        +       NaOH      --->      NaCl + H2O

25.0 ml            
0.150 M            0.250M

2) 50% completion => 0.025 l * 0.150 M * (1/2) = 0.001875 mol HCl consumed and 0.001875 mol HCl in solution

0.001875 mol HCl => 0.001875 mol H(+)

Volume = Volume of HCl solution + Volumen of NaOH solution added

Volume of HCl solution = 0.0250 l

Volume of NaOH = n / M = 0.001875 mol / 0.250M = 0.0075 l

Total volume = 0.0250 l + 0.0075 l = 0.0325 l

[H+] = 0.001875 mol / 0.0325 l = 0.05769 M

pH = - log [H+] = - log (0.05769) = 1.23

Answer: 1.23

3) Equivalence point

0.02500 l * 0.150 M = 0.250M * V

=> V = 0.02500 * 0.150 / 0.250 = 0.015 l

4) 1.00 ml NaOH added beyond the equivalence point

1.00 ml * 1 l / 1000 ml * 0.250 M = 0.00025 mol NaOH in excess

0.00025 mol NaOH = 0.00025 mol OH-

Volume of the solution = 0.02500 l + 0.015 l + 1.00/1000 l = 0.041 l

[OH-] = 0.00025 mol / 0.041 l = 0.00610 M

pOH = - log (0.00610) = 2.21

pH + pOH = 14 => pH = 14 - pOH = 14 - 2.21 = 11.76

Answer: 11.76
6 0
4 years ago
Consider the following reaction:
Sidana [21]
Your limiting is CuCI2 and the excess is KI (from what i’ve heard from my tc to find it just use the moles or look at the grams)Do you want me to do the qn and give u the ans or?

Explanation:You have more grams of KI than CuCI2
irl example : I need 200g of flour to bake 1 muffin and 100g of butter.But I have 300g of butter and only 200g of flour.This means I can only bake up to 1 muffin since I got excess grams of butter.But to use up all my 300g of butter I need 400g more of flour.Making my butter the excess while my flour the limiting since I have less of it and it also determines how much muffin would I get at the end of the bake.

im sorry if that example sounds clowny T-T
6 0
3 years ago
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