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3 years ago

What are the 3 types of water?

Chemistry

2 answers:

omeli [17]3 years ago

8 0

Solid liquid gas. .

Irina18 [472]3 years ago

4 0

Answer:

3 Types of Water: Mineral, Spring and Prepared Water

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Under the same conditions of solar radiation, compared with oceans the land will warm_________

aksik [14]

Land will warm faster/quicker

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3 years ago

A 133.8-gram sample of bronze was 10.3% tin by mass. Determine the total mass of tin in the sample.

Kay [80]

You just need to multiply the total mass by the decimal value of the part that is tin. 133.8*0.103=13.8g (following the rules of significant figures).

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3 years ago

Which of the following is TRUE? A) The equivalence point is where the amount of acid equals the amount of base during any acid-b

liberstina [14]

Answer:

the correct option is B

Explanation:

The correct option is b, since if we reach pH 7, it means that the acid-base reaction is neutralized, therefore the base has been neutralized by an acid or vice versa, without taking into account the proteins or the amounts of both components .

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3 years ago

Read 2 more answers

How many moles of CH4 are in 148.6 g? Round your answer to two decimal places.

Dafna1 [17]

Answer:

9.29 mol

Explanation:

Given data:

Number of moles = ?

Mass = 148.6 g

Solution:

Number of moles = mass/ molar mass

Molar mass of CH₄ = 16 g/mol

Now we will put the values in formula.

Number of moles = 148.6 g/ 16 g/mol

Number of moles = 9.29 mol

Thus 148.6 g have 9.29 moles.

6 0

3 years ago

Given 3.4 grams of x compound with a molar mass of 85 g and 4.2 grams of y compound with a molar mass of 48 g How much of compou

Ulleksa [173]

Answer:

$4.36~g~XY$

Explanation:

In this case, we can start with the reaction:

$2X + Y_2~->~2XY$

If we check the reaction, we will have 2 X and Y atoms on both sides. So, the reaction is balanced. Now, the problem give to us two amounts of reagents. Therefore, we have to find the limiting reagent. The first step then is to find the moles of each compound using the molar mass:

$3.4~g~X\frac{1~mol~X}{85~g~X}=0.04~mol~X$

$4.2~g~Y_2\frac{1~mol~Y_2}{48~g~Y_2}=0.0875~mol~Y_2$

Now, we can divide by the coefficient of each compound (given by the balanced reaction):

$\frac{0.04~mol~X}{1}=~0.04$

$\frac{0.0875~mol~Y_2}{2}=0.04375$

The smallest value is for "X", therefore this is our limiting reagent. Now, if we use the molar ratio between "X" and "XY" we can calculate the moles of XY, so:

$0.04~mol~X\frac{2~mol~XY}{2~mol~X}=0.04~mol~XY$

Finally, with the molar mass of "XY" we can calculate the grams. Now, we know that 1 mol X = 85 g X and 1 mol $Y_2$ = 48 g $Y_2$ (therefore 1 mol Y = 24 g Y). With this in mind the molar mass of XY would be 85+24 = 109 g/mol. With this in mind:

$0.04~mol~XY\frac{109~g~XY}{1~mol~XY}=4.36~g~XY$

I hope it helps!

6 0

3 years ago

What are the 3 types of water?​

What are the 3 types of water?