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Alexus [3.1K]
3 years ago
15

A rocket powered sled is accelerating along a straight, level track with a constant acceleration of magnitude 20 m/s2. By how mu

ch will the speed of the sled change in 3.00 seconds
Physics
1 answer:
Dafna1 [17]3 years ago
7 0

Answer:

the change in speed of the sled after 3.0 s is 60 m/s.

Explanation:

Given;

constant acceleration of the sled, a = 20 m/s²

change in time of motion, dt = 3.0 s

The change in speed of the sled after 3.0 s is calculated as;

a = \frac{dv}{dt} \\\\dv = a \times dt\\\\dv = 20 \ \times \ 3\\\\dv = 60 \ m/s

Therefore, the change in speed of the sled after 3.0 s is 60 m/s.

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A 1.25 x 10-4 C charge is moving5200 m/s at 37.0° to a magnetic fieldof 8.49 x 10-4 T. What is the magneticforce on the charge?
juin [17]

0.0003321 Newtons

Explanation

We are given the charge, its velocity, and the magnetic field strength and direction. We can thus use the equation to find the force

\begin{gathered} F=qvBsinθ \\ where\text{ F is the magnetic force} \\ q\text{ is the charge} \\ v\text{ is the velocity of the charge} \\ Bis\text{ the magnetic field} \\ \theta\text{ is the angle} \end{gathered}

so

Step 1

Let

\begin{gathered} q=1.25*10^{-4\text{ }}C \\ v=5200\frac{m}{s} \\ \theta=37\text{ \degree} \\ B=8.49*10^{-4}T \end{gathered}

now, replace

\begin{gathered} F=qvBs\imaginaryI n\theta \\ F=1.25*10^{-4}\text{ C*5200 }\frac{m}{s}*8.49*10^{-4}Tsin(37) \\ F=0.0003321\text{ Newtons} \\  \end{gathered}

so, the answer is

0.0003321 Newtons

I hope this helps you

7 0
1 year ago
What are the two forces that oppose each other while a star?
Rufina [12.5K]
While self-gravity pulls the star inward and tries to make it collapse, thermal pressure (heat created by fusion) pushes outward. These two forces cancel each other out in a main sequence star, thus making it stable.
5 0
3 years ago
What is the component of d1 along the direction of d2?
aniked [119]
I don't know lol hahahahhahahahahahahahahahahahahaha
8 0
3 years ago
Please help!!! I have a physics exam tomorrow and I just can't wrap my head around this one!
Ainat [17]

The total electrostatic force on charge A is 28 \mu N

Explanation:

The magnitude of the electrostatic force between two charges is given by Coulomb's law:

F=k\frac{q_1 q_2}{r^2}

where:

k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q_1, q_2 are the two charges

r is the separation between the two charges

Here we have three positively charged particles A,B and C, located at the following positions:

x_A = 0\\x_B = 10 m\\x_C = 20 m

The magnitudes of the three charges are:

q_A = q_B = q_C = 0.5 \mu C = 0.5\cdot 10^{-6}C

The force exerted by B on A is to the left (because the force between two positive charges is repulsive), and the force exerted by C on A is also to the left (also repulsive). Therefore, the net force on A is just the sum of the two forces exerted by charges B and C:

F_A = F_{BA} + F_{CA} = k\frac{q_B q_A}{(x_B-x_A)^2}+k\frac{q_C q_A}{(x_C-x_A)^2}=\\=(8.99\cdot 10^9) \frac{(0.5\cdot 10^{-6})^2}{(10)^2}+(8.99\cdot 10^9) \frac{(0.5\cdot 10^{-6})^2}{(20)^2}=2.8\cdot 10^{-5} N = 28 \mu N

Learn more about electric force:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

3 0
3 years ago
Two technicians are discussing the testing of a catalytic converter. Technician A says that a vacuum gauge can be used and obser
Andrej [43]

Answer:

Answer is C. Both technicians A and B.

Refer below.

Explanation:

Two technicians are discussing the testing of a catalytic converter. Technician A says that a vacuum gauge can be used and observed to see if the vacuum drops with the engine at 2500 RPM for 30 seconds. Technician B says that a pressure gauge can be used to check for backpressure. The following technician is correct:

Both technicians A and B

7 0
3 years ago
Read 2 more answers
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