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Alexus [3.1K]
3 years ago
15

A rocket powered sled is accelerating along a straight, level track with a constant acceleration of magnitude 20 m/s2. By how mu

ch will the speed of the sled change in 3.00 seconds
Physics
1 answer:
Dafna1 [17]3 years ago
7 0

Answer:

the change in speed of the sled after 3.0 s is 60 m/s.

Explanation:

Given;

constant acceleration of the sled, a = 20 m/s²

change in time of motion, dt = 3.0 s

The change in speed of the sled after 3.0 s is calculated as;

a = \frac{dv}{dt} \\\\dv = a \times dt\\\\dv = 20 \ \times \ 3\\\\dv = 60 \ m/s

Therefore, the change in speed of the sled after 3.0 s is 60 m/s.

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Answer:

P1 = 240 kPa.

Explanation:

Given the following data;

Initial volume = 0.3 m³

Final volume, V2 = 0.9 m³

Final pressure, P2 = 80 kPa

To find the initial pressure, we would use Boyle's law;

Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.

Mathematically, Boyles law is given by the formula;

PV = K

P_{1}V_{1} = P_{2}V_{2}

Substituting into the formula, we have;

P_{1} * 0.3 = 80 * 0.9

0.3P_{1} = 72

P_{1} = \frac {72}{0.3}

P_{1} = 240

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Hop this helps and can u think about brainlist

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