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avanturin [10]
3 years ago
7

A snowmobile has an initial velocity of 4.7 m/s.

Physics
1 answer:
zimovet [89]3 years ago
3 0
Q1. The answer is 8.788 m/s

V2 = V1 + at
V1 - the initial velocity
V2 - the final velocity
a - the acceleration
t - the time

We have:
V1 = 4.7 m/s
a = 0.73 m/s²
t = 5.6 s
V2 = ?

V2 = 4.7 + 0.73 * 5.6
V2 = 4.7 + 4.088
V2 = 8.788 m/s


Q2. The answer is 9.22 s

V2 = V1 + at
V1 - the initial velocity
V2 - the final velocity
a - the acceleration
t - the time

We have:
V2 = 0   (because it reaches a complete stop)
V1 = 4.7 m/s
a = -0.51 m/s²
t = ?

0 = 4.7 + (-0.51)*t
0 = 4.7 - 0.51t
0.51t = 4.7
t = 4.7 / 0.51
t = 9.22 s
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Answer:4.22 J

Explanation:

Given

mass of pitcher m=2.6\ kg

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distance moved s=48\ cm

Applying work-Energy theorem which states that work done by all the forces is equal to the change in kinetic energy of the object

Work done by force W=F\cdot s

W=8.8\times 0.48 J

change in kinetic Energy =\frac{1}{2}mv^2-0

8.8\times 0.48=\Delta K.E.

K.E.-0=4.22

K.E.=4.22\ J

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10 N.m

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Force * Perpendicular distance.

= 20 N * 0.5 m

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An object with a mass of 70 kilograms is supported at a height 8 meters above the ground. What's the potential energy of the obj
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Ep= 5,488J
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2. What is the total effect of sound produced in an enclosed space called?
Igoryamba
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A rocket accelerates by burning its onboard fuel, so its mass decreases with time. Suppose the initial mass of the rocket at lif
Serggg [28]

Answer:

Height of the rocket be one minute after liftoff is 40.1382 km.

Explanation:

v(t)=-gt-v_e\times \ln \frac{m-rt}{m}

v = velocity of rocket at time t

g = Acceleration due to gravity =9.8 m/s^2

v_e = Constant velocity relative to the rocket = 2,900m/s.

m = Initial mass of the rocket at liftoff = 29000 kg

r = Rate at which fuel is consumed = 170 kg/s

Velocity of the rocket after 1 minute of the liftoff =v

t = 1 minute = 60 seconds'

Substituting all the given values in in the given equation:

v(60)=-9.8 m/s^2\times 60 s-2,900m/s\times \ln (\frac{29,000 kg-170 kg/s\times 60 s}{2,9000 kg})

v(60) = 668.97 m/s

Height of the rocket = h

Velocity=\frac{Displacement}{time}

668.97 m/s=\frac{h}{60 s}

h=668.97 m/s\times 60 s=40,138.2 m = 40.1382 km

Height of the rocket be one minute after liftoff is 40.1382 km.

4 0
3 years ago
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