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4 years ago

Please help legit things only or you get banned thanks!!!!!!!!!!!!!

Mathematics

1 answer:

fgiga [73]4 years ago

6 0

Answer: B if I'm rong sue me

Step-by-step explanation:

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Multiple Choice: What method can be used to prove the triangles below are congruent? * Angle Side Angle (ASA) Angle Angle Side (

Aneli [31]

Answer:

angle side angle

Step-by-step explanation:

3 0

3 years ago

A shirt is regularly priced at 42$. It is on sale for 15% off of the regular price. What is the sale price of the shirt ?

gulaghasi [49]

Answer:

$35.7

Step-by-step explanation:

you can convert 15% to a decimal by dividing by 100.

15/100 = .15

if you multiply the decimal by the cost of the shirt you get how much the discount is.

0.15 * $42 = 6.30

so a 15% discount on a $42 shirt is $6.30 off. So you subtract the discount from the total cost.

$42 - $6.30 = $35.70 that is the sale price of the shirt.

4 0

3 years ago

Read 2 more answers

given that sin theta= 1/4, 0 is less than theta but less than pi/2, what is the exact value of cos theta

lapo4ka [179]

Answer:

$\cos{\theta} = \frac{\sqrt{15}}{4}$

Step-by-step explanation:

For any angle $\theta$ , we have that:

$(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1$

Quadrant:

$0 \leq \theta \leq \frac{\pi}{2}$ means that $\theta$ is in the first quadrant. This means that both the sine and the cosine have positive values.

Find the cosine:

$(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1$

$(\frac{1}{4})^{2} + (\cos{\theta})^{2} = 1$

$\frac{1}{16} + (\cos{\theta})^{2} = 1$

$(\cos{\theta})^{2} = 1 - \frac{1}{16}$

$(\cos{\theta})^{2} = \frac{16-1}{16}$

$(\cos{\theta})^{2} = \frac{15}{16}$

$\cos{\theta} = \pm \sqrt{\frac{15}{16}}$

Since the angle is in the first quadrant, the cosine is positive.

$\cos{\theta} = \frac{\sqrt{15}}{4}$

3 0

3 years ago

-8>4+2v<br> How do you do this

Natalija [7]

Answer:

v = -6

Step-by-step explanation:

I am SMAT

6 0

3 years ago

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Math question down below

Alja [10]

Answer:

E is the only one that ends with 70 and is also all multiples of 6.

4 0

4 years ago