If f(x) = (xm + 9)2, which statement about f(x) is true?
2 answers:
I would say none of these .
for x to be even then f(x) = f(-x) for all values of x in the domain.
Suppose x=1 and m=1 then f(x) = 20. f(-1) is 16 so f(x) does not equal f(-x)
for it to be odd then either f(x) = -f(x) or f(x) + f(-x) = 0 . Looking at teh above example neither is true.
That is an odd value of m . if you use m=2 you have exactly the same effect so its not even or odd for an even value of m.
So unless you've got a very restricted domain for the function none of these statements are true.
Answer: The answer is b
f(x) is an even function for all even values of m
Step-by-step explanation:
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Answer:
no
Step-by-step explanation:
2x + 9 = 35
We subtract 9 in both sides:
2x + 9 - 9 = 35 - 9
2x = 26
We then divide 2 in both sides:
x = 13
