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2 years ago

Consider the system of equations.

Mathematics

2 answers:

Agata [3.3K]2 years ago

6 0

Answer:

C) The second equation converted to slope-intercept form is .y = negative one-third x minus 1

Step-by-step explanation:

wlad13 [49]2 years ago

5 0

Answer:

c on edge

Step-by-step explanation:

Consider the system of equations.

y = –2x + 4,

3y + x = –3

Which statement is true of this system of equations?

Both equations are in slope-intercept form.

The first equation converted to slope-intercept form is y + 2x = 4.

The second equation converted to slope-intercept form is .y = negative one-third x minus 1

Neither equation is in slope-intercept form.

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Writing to Explain Suppose you have a 100-mL cup, you can a 500-mL cup. List two different ways

Misha Larkins [42]

5 100ml cups and 1 500 ml cup

and 2 500 ml cups

4 0

3 years ago

Which expression is equivalent sqrt10/4sqrt8

N76 [4]

Answer:

The correct option is A

Step-by-step explanation:

The given expression is:

√10/4√8

We have to eliminate the √ from the denominator

4√8 = (2^3)^1/4

Multiply the whole expression by (2)^1/4

=(2)^1/4 * √10/ 2^(1/4)*(2^3)^(1/4)

= 2^(1/4) · 10^(2/4) / 2^1/4+3/4

=2^(1/4) · 10^(2/4) / 2^1+3/4

=2^(1/4) · 10^(2/4) / 2^4/4

=2^(1/4) · 10^(2/4) /2

=2^(1/4) · 100^(1/4) /2

=200^1/4 /2

= 4√200 /2

Thus the correct option is A....

3 0

3 years ago

What is the slope of the line? Please help :)

Anuta_ua [19.1K]

Answer:

The slope of line is 2/3.

Step-by-step explanation:

To calculate slope you do :

y2 - y1 / x2 - x1

6 0

3 years ago

Read 2 more answers

Find the area of the composite figure.

Roman55 [17]

Answer:

The Area of the composite figure would be 76.26 in^2

Step-by-step explanation:

According to the Figure Given:

Total Horizontal Distance = 14 in

Length = 6 in

To Find :

The Area of the composite figure

Solution:

Firstly we need to find the area of Rectangular part.

So We know that,

$\boxed{ \rm \: Area \: of \: Rectangle = Length×Breadth}$

Here, Length is 6 in but the breadth is unknown.

To Find out the breadth, we’ll use this formula:

$\boxed{\rm \: Breadth = total \: distance - Radius}$

According to the Figure, we can see one side of a rectangle and radius of the circle are common, hence,

$\longrightarrow\rm \: Length \: of \: the \: circle = Radius$

Since Length = 6 in ;

$\longrightarrow \rm \: 6 \: in = radius$

Hence Radius is 6 in.

So Substitute the value of Total distance and Radius:

Total Horizontal Distance= 14
Radius = 6

$\longrightarrow\rm \: Breadth = 14-6$

$\longrightarrow\rm \: Breadth = 8 \: in$

Hence, the Breadth is 8 in.

Then, Substitute the values of Length and Breadth in the formula of Rectangle :

Length = 6
Breadth = 8

$\longrightarrow\rm \: Area \: of \: Rectangle = 6 \times 8$

$\longrightarrow \rm \: Area \: of \: Rectangle = 48 \: in {}^{2}$

Then, We need to find the area of Quarter circle :

We know that,

$\boxed{\rm Area_{(Quarter \; Circle) } = \cfrac{\pi{r} {}^{2} }{4}}$

Now Substitute their values:

r = radius = 6
π = 3.14

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times 6 {}^{2} }{4}$

Solve it.

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times 36}{4}$

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times \cancel{{36} } \: ^{9} }{ \cancel4}$

$\longrightarrow\rm Area_{(Quarter \; Circle)} =3.14 \times 9$

$\longrightarrow\rm Area_{(Quarter \; Circle) } = 28.26 \: {in}^{2}$

Now we can Find out the total Area of composite figure:

We know that,

$\boxed{ \rm \: Area_{(Composite Figure)} =Area_{(rectangle)}+ Area_{ (Quarter Circle)}}$

So Substitute their values:

$\rm Area_{(rectangle)}$ = 48
$\rm Area_{(Quarter Circle)}$ = 28.26

$\longrightarrow \rm \: Area_{(Composite Figure)} =48 + 28 .26$

Solve it.

$\longrightarrow \rm \: Area_{(Composite Figure)} =\boxed{\tt 76.26 \:\rm in {}^{2}}$

Hence, the area of the composite figure would be 76.26 in² or 76.26 sq. in.

$\rule{225pt}{2pt}$

I hope this helps!

3 0

2 years ago

Please help this hurts

Svetllana [295]

Answer:

6x - 11y = -13 is the answer.

Step-by-step explanation:

Let's plug in the points to see what sticks.

Start with (-4, -1)

1) 11x - 6y = 11(-4) - 6(-1) = -44 + 6 = -38 $\neq$ 13

2) 6x - 11y = 6(-4) - 11(-1) = -24 + 11 = -13

3) 6x - 7y = 6(-4) - 7(-1) = -24 + 7 = -17 $\neq$ 17

4) 6x - 11y = 6(-4) - 11(-1) = -24 + 11 = -13 $\neq$ 13

The only one that fits is #2. Let's try the other point to be sure.

2) 6x - 11y = 6(1.5) - 11(2) = 9 - 22 = -13

3 0

3 years ago