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azamat
3 years ago
5

Consider the system of equations.

Mathematics
2 answers:
Agata [3.3K]3 years ago
6 0

Answer:

C) The second equation converted to slope-intercept form is .y = negative one-third x minus 1

Step-by-step explanation:

wlad13 [49]3 years ago
5 0

Answer:

c on edge

Step-by-step explanation:

Consider the system of equations.

y = –2x + 4,

3y + x = –3

Which statement is true of this system of equations?

Both equations are in slope-intercept form.

<em><u>T</u></em>he first equation converted to slope-intercept form is y + 2x = 4.

<u><em>The second equation converted to slope-intercept form is .y = negative one-third x minus 1</em></u>

Neither equation is in slope-intercept form.

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Solve for pizza in the pie chart!
solniwko [45]

Answer:

24

Step-by-step explanation:

30% of the pie chart is pizza. 30% of 80 = 0.3 * 80 = 24

6 0
3 years ago
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-3(8n+10) <br> distributive property
Lerok [7]
-24n - 30, i suggest using math.way before asking a math question aha
6 0
3 years ago
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If the coordinates of the endpoints of a diameter of the circle are​ known, the equation of a circle can be found.​ First, find
Evgesh-ka [11]

Answer:

The equation of the circle is (x+3)^2+(y-5)^2 = 17

Step-by-step explanation:

The complete question is

If the coordinates of the endpoints of a diameter of the circle are​ known, the equation of a circle can be found.​ First, find the midpoint of the​ diameter, which is the center of the circle. Then find the​ radius, which is the distance from the center to either endpoint of the diameter. Finally use the​ center-radius form to find the equation.

Find the center-radius  form of the circle having the points (1,4) and (-7,6) as the endpoints of a diameter.

Consider that, if both points are the endpoints of a diameter, the center of the circle is the point that is exactly in the middle of the two points (that is, the point whose distance to each point is equal). Given points (a,b) and (c,d), by using the distance formula, you can check that the middle point is the average of the coordinates. Hence, the center of the circle is given by

(\frac{1-7}{2}, \frac{4+6}{2}) = (-3,5).

We will find the radius. Recall that the radius of the circle is the distance from one point of the circle to the center. Recall that the distance between points (a,b) and (c,d) is given by \sqrt[]{(a-c)^2+(b-d)^2}. So, let us use (1,4) to calculate the radius.

r = \sqrt[]{(1-(-3))^2+(4-5)^2} = \sqrt[]{17}.

REcall that given a point (x_0,y_0). The equation of a circle centered at the point (x_0,y_0) is

(x-x_0)^2+(y-y_0)^2 = r^2

In our case, (x_0,y_0)=(-3,5) and r=\sqrt[]{17}. Then, the equation is

(x-(-3))^2+(y-5)^2 = (x+3)^2+(y-5)^2 = 17

4 0
3 years ago
Consider two boxes, one containing one black and one white marble, the other, two black and one white marble. A box is selected
valina [46]

Answer:

\frac{7}{12}

Step-by-step explanation:

Probability refers to chance of happening of some event.

Conditional probability is the probability of an event A, given that another event B has already occurred.

B_1,B_2 denote the two boxes.

In box B_1:

No. of black balls = 1

No. of white balls = 1

In box B_2:

No. of black balls = 2

No. of white balls = 1

Let B, W denote black and white marble.

So, probability that either of the boxes B_1,B_2 is chosen is \frac{1}{2}

Probability that a black ball is chosen from box B_1 = \frac{1}{2}

Probability that a black ball is chosen from box B_2=\frac{2}{3}

To find:probability that the marble is black

Solution:

Probability that the marble is black = \frac{1}{2}(\frac{1}{2} )+\frac{1}{2}(\frac{2}{3})=\frac{1}{4}+\frac{1}{3}=\frac{7}{12}

6 0
3 years ago
Construct 3 linear equation starting with qiven solution z = 1/3
Andreyy89

Answer:

(a)9z+2=5

(b)21z-11=-4

(c)4z=2-2z

Step-by-step explanation:

We are required to construct 3 linear equations starting with the given solution z = 1/3.

<u>Equation 1</u>

<u />z=\frac{1}{3}<u />

Multiply both sides by 9

9z=\frac{1}{3}\times 9\\9z=3

Rewrite 3 as 5-2

9z=5-2

Add 2 to both sides

Our first equation is: 9z+2=5

<u>Equation 2</u>

<u />z=\frac{1}{3}<u />

Multiply both sides by 21

21z=\frac{1}{3}\times 21\\21z=7

Rewrite 7 as 11-4

21z=11-4

Subtract 11 from both sides

Our second equation is: 21z-11=-4

<u>Equation 3</u>

<u />z=\frac{1}{3}<u />

Multiply both sides by 6

6z=\frac{1}{3}\times 6\\6z=2

Rewrite 6z as 4z+2z

4z+2z=2

Subtract 2z from both sides

Our third equation is: 4z=2-2z

4 0
3 years ago
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