<u>Answer:</u> The amount of energy absorbed by water is 5390 Calories
<u>Explanation:</u>
To calculate the amount of heat absorbed at normal boiling point, we use the equation:
where,
q = amount of heat absorbed = ?
m = mass of water = 10 grams
= latent heat of vaporization = 539 Cal/g
Putting values in above equation, we get:
Hence, the amount of energy absorbed by water is 5390 Calories
I thinks it's true but I'm not sure
Answer:
Explanation:
Increasing Volume while maintaining constant pressure requires a proportional increase in Temperature so the gas pressure will be maintained as constant.
Consider...
V₁ = V₁ V₂ = 4V₁
T₁ = T₁ T₂ = ?
Charles Law => T ∝ V at constant P ... that is, increasing temperature generates a proportional increase in volume to maintain constant pressure.
Empirical Charles Law Relation is ...
V₁/T₁ = V₂/T₂ => T₂ = T₁(V₂/V₁) = T₁(4V₁/V₁) = 4T₁
Increasing Volume of a gas by 4 times requires a 4 times increase in absolute temperature in order to maintain constant pressure.
