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Monica [59]
2 years ago
5

The pressure needed to pump blood back to the heart is produced by the _____.

Chemistry
1 answer:
PolarNik [594]2 years ago
4 0

Answer:

A. body muscles

The pressure needed to pump blood back to the heart is produced by the <u>body </u><u>muscles </u><u>.</u>

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Rewrite each percent as a fraction and decimal 56%
Tasya [4]
I know the decimal is .56 i hope someone knows the fraction
Add Me!
6 0
3 years ago
Movement of a substance from a point of higher concentration to a point of lower concentration is known as
amm1812
The answer is diffusion.
7 0
3 years ago
If 15g of iron reacts with 8.5g of oxygen, how many grams of iron oxide will be produced
just olya [345]

Answer:

23.5g of FeO

Explanation:

Hello,

The question above is asking us to find the mass of iron oxide produced from 15g of Fe and 8.5g of O. Well, to solve this question, we'll require the equation of reaction.

2Fe + O₂ → 2FeO

From the equation of reaction, 2 moles of Fe plus 1 mole of oxygen will produce 2 moles of FeO

Molar mass of Fe = 56g/mol

Molar mass of FeO = 72g/mol

Molar mass of O = 16 × 2 = 32g/mol

Number of moles = mass / molar mass

Mass = number of moles × molar mass

Mass of Fe = 2 × 56 = 112g

Mass of O = 32g

Mass of FeO = 2 × 72 = 144g

From the equation of reaction, (112 + 32)g (Fe + O2) reacts to produce 144g of FeO

114g of reacts produce 114g of FeO

15g of Fe + 8.5g of O2 = ?

(15 + 8.5)g (Fe + O2) = x

X = (23.5 × 114) / 114

x = 23.5g

Therefore, 15g of Fe and 8.5g of O2 will react to produce 23.5g of FeO

6 0
3 years ago
n atom “likes” to obtain a full outer shell. The fourth shell (in the atoms that we are studying today) can hold a maximum of 8
fgiga [73]

It depends on how many electrons are already in the outer shell.

If it is a large amount (if it is almost to the maximum), then it will want to borrow from another atom.

But if it is close to empty then it will want to give away so it will go back to the inner ring with will be full.

Hope this helps, good luck!

4 0
3 years ago
A solution is prepared by dissolving 0.5636 g oxalic acid (H2C2O4) in enough water to make 100.0 mL of solution. A 10.00-mL aliq
zepelin [54]

Answer:

The final molarity of the diluted oxalic acid solution is 0.002504 M

Explanation:

Step 1: Data given

Mass of oxalic acid (H2C2O4) = 0.5636 grams

Volume of the solution = 100.0 mL = 0.100 L

A 10 ml of this solution diluted in 250 ml of solution.

Molecular weight of H2C2O4  = 90.03 g/mol

Step 2: Calculate  initial moles of H2C2O4

Moles H2C2O4  = mass / molar mass

Moles H2C2O4  = 0.5636 grams / 90.03 g/mol

Moles H2C2O4 = 0.00626 moles

Step 3: Calculate molarity of the solution

Molarity = moles / volume

Molarity = 0.00626 moles / 0.100 L

Molarity = 0.0626 M

Step 4: Calculate moles of a 10.00 mL aliquot

Moles = 0.0626 M * 0.010 L

Moles = 0.000626 moles

Step 5: Calculate the new molarity

Molarity = 0.000626 moles / 0.250 L

Molarity = 0.002504 M

The final molarity of the diluted oxalic acid solution is 0.002504 M

6 0
3 years ago
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