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2 years ago

For a Brainlist and explain

Mathematics

1 answer:

Katena32 [7]2 years ago

7 0

Answer:

c is your answer

Step-by-step explanation:

please mark brailiest

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Please help me with this someone please explain and show your full work

Marysya12 [62]

1. I am guessing the triangles split the bottom in half so you will find the area of the triangles and the rectangle and add them together
Triangle=3×4 /2 12/2=6
Triangle 3×4 /2 6
Rectangle: 8×1 8
6+6+8=
12+8=20m^2

2. Triangle area+rectangle area
Rectangle: 22×24 528
Triangle: 8×24 /2 192/2 96
528+96= 624

5 0

3 years ago

Question 1: 3/4n+16=2-1/8n. Show work plzz for all i need help due tomorrow!!!

Bezzdna [24]

1) Multiply everything by 8. It clears the fractions.
It gives you 6n + 128 =16 - n
You add the -n to the other side of the equation.
It gives you 7n + 128= 16
You then subtract 128 from 16.
It gives you 7n= -112
You divide everything by 7
It gives you n=-17

7 0

2 years ago

Dy/dx = 2xy^2 and y(-1) = 2 find y(2)

Anarel [89]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2887301

—————

Solve the initial value problem:

dy
——— = 2xy², y = 2, when x = – 1.
dx

Separate the variables in the equation above:

$\mathsf{\dfrac{dy}{y^2}=2x\,dx}\\\\
\mathsf{y^{-2}\,dy=2x\,dx}$

Integrate both sides:

$\mathsf{\displaystyle\int\!y^{-2}\,dy=\int\!2x\,dx}\\\\\\
\mathsf{\dfrac{y^{-2+1}}{-2+1}=2\cdot \dfrac{x^{1+1}}{1+1}+C_1}\\\\\\
\mathsf{\dfrac{y^{-1}}{-1}=\diagup\hspace{-7}2\cdot \dfrac{x^2}{\diagup\hspace{-7}2}+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{y}=x^2+C_1}$

$\mathsf{\dfrac{1}{y}=-(x^2+C_1)}$

Take the reciprocal of both sides, and then you have

$\mathsf{y=-\,\dfrac{1}{x^2+C_1}\qquad\qquad where~C_1~is~a~constant\qquad (i)}$

In order to find the value of C₁ , just plug in the equation above those known values for x and y, then solve it for C₁:

y = 2, when x = – 1. So,

$\mathsf{2=-\,\dfrac{1}{1^2+C_1}}\\\\\\
\mathsf{2=-\,\dfrac{1}{1+C_1}}\\\\\\
\mathsf{-\,\dfrac{1}{2}=1+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-1=C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-\dfrac{2}{2}=C_1}$

$\mathsf{C_1=-\,\dfrac{3}{2}}$

Substitute that for C₁ into (i), and you have

$\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}}\\\\\\
\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}\cdot \dfrac{2}{2}}\\\\\\
\mathsf{y=-\,\dfrac{2}{2x^2-3}}$

So y(– 2) is

$\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot (-2)^2-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot 4-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{8-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{5}}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

Tags: <em>ordinary differential equation ode integration separable variables initial value problem differential integral calculus</em>

7 0

3 years ago

Type the correct equation of the line. (0, 1), (2, -3), (4, -7)

amid [387]

Answer:

1(2-3)(4-7)

(1)(-1)(4-7)

-1(4-7)

(-1)(-3)

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

A portion of a map with cities a and b is shown.The map uses a scale of 1 inch to 30 miles. A new map has a scale of 2 inches=15

Alina [70]

Answer:

22.5miles

Step-by-step explanation:

For Map 1;

1 inches = 30miles

For Map 2:

2 inches = 15miles

1 inches = x

2x = 1 *15

x = 15/2

x = 7.5miles

This means that 1 inch represents 7.5miles on Map 2'

The distance between the two cities in miles = 30miles - 7.5miles

The distance between the two cities (in miles) = 22.5miles

3 0

2 years ago