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2 years ago

Select the correct answer. Evaluate the following expression when x = -4 and y = 4. A. B. C. D.

Mathematics

1 answer:

andriy [413]2 years ago

3 0

The value of given expression when x=-4 and y=4 is 1250.

The expression is missing in the question which is $\dfrac{x^6-x}{4y}$ .

We have to solve it for x= -4 and y = 4.

Now putting the value of x and y we get,

$\dfrac{x^6-x}{4y}=\dfrac{(-4)^6-(-4)}{4}$

$\dfrac{x^6-x}{4y}=\dfrac{4096+4}{4}$

$\dfrac{x^6-x}{4y}=1250$

Hence the value of given expression when x=-4 and y=4 is 1250.

For more details follow the link:

brainly.com/question/11897796

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garik1379 [7]

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3 years ago

Read 2 more answers

The fifth graders to plant a butterfly garden. Clover grows in ½ of the garden, daisies in ¼ of the garden, coneflowers in ⅛ of

olchik [2.2K]

Answer:

Fraction of the garden used = $\frac{5}{8}$

Step-by-step explanation:

The fifth graders to plant a butterfly garden.

We are given that

Clover grows in ½ of the garden

Daisies grow in ¼ of the garden

Coneflowers grow in ⅛ of the garden

milkweed grows in ⅛ of the garden

The fifth graders notice that the butterflies land on the clover and milkweed.

We are asked to find out the fraction of the garden that the butterflies used.

Fraction of the garden used = clover + milkweed

Fraction of the garden used = $\frac{1}{2} + \frac{1}{8}$

The LCM of 2 and 8 is 8

Fraction of the garden used = $\frac{4 +1}{8}$

Fraction of the garden used = $\frac{5}{8}$

Therefore, the butterflies used $\frac{5}{8}$ fraction of the garden.

6 0

3 years ago

Determine if the equation below is a function with independent variable x. If so, find the domain. If not, find a value of x to

Andre45 [30]

Answer:

No because it contains points (3,4) and (3,-4). You cannot have a x assigned to more than one y-value if you want it to be a function.

Step-by-step explanation:

A function has one output per input.

If we are trying to determine if the given is a function of x, then x is the input.

However I can get two outputs from plugging in x=3.

$3^2+y^2=25$

$9+y^2=25$

Subtract 9 on both sides:

$y^2=25-9$

$y^2=16$

Take the square root of both sides:

$y=\pm \sqrt{16}$

$y=\pm 4$ .

So input x=3 yields y=4 and y=-4.

Since this input has more than one output then the given is not a function of x.

----Also!

If you graph the equation, it is a circle with radius 5 and center (0,0). So I could I plug in any number for x between -5 and 5 excluding -5 and 5 which would yield only one output each. Since plugging in either one gives:

$(\pm 5)^2+y^2=25$