Which place is the 0 in? 10.56

Mathematics

1 answer:

xxMikexx [17]3 years ago

3 0

Answer:

counting from the left, the number 0 is the second number and it's the number In the unit position

Step-by-step explanation:

The position of number 0 in 10.56 is to be determined by first identifying the llrank of numbers in 10.56

Starting with first

1 : the number 1 is in the ten position

0: the number 0 is in the unit position

5: the number 5 is in the tenth position which is the position immediatly after the decimal.

6: The number 6 is in the hundredth position which is the position after the first number after the decimal

But the counting from the left, the number 0 is the second number and it's the number In the unit position

You might be interested in

Explain how to write a whole number as a fraction with a denominator of 1

Troyanec [42]

Answer:

All you need to do is write the whole number and then a slash with the denominator of 1. For example: you would write 5 as 5/1 in fraction form

Step-by-step explanation:

6 0

3 years ago

(a)

Umnica [9.8K]

H. hopedwpww
y
y w
haughty. y y

how he’d yy. at he

5 0

3 years ago

If the circumference of a circle is 36π, what is the length of a radius of the circle?

m_a_m_a [10]

Answer:

The answer is 6 (A)

Step-by-step explanation:

The exact answer is 5.73, but I think in the question they are rounding to the nearest whole number, so the rounded answer is 6.

My work:

C = 2πr

r = C

2π = 36

2·π = 5.72958

8 0

3 years ago

Find the sum. r/r^2-q^2 + 5/r+q

pickupchik [31]

Answer:

The answer is:

$\frac{6r-5q}{r^2-q^2}$

which agrees with the last answer option (D) in the list.

Step-by-step explanation:

In order to add rational expressions, we need to express them with the same denominator. Therefore we examine what factors there are in the first denominator, which happens to be a difference of squares which is readily factored out as:

$r^2-q^2=(r+q)\,(r-q)$

the second denominator consists of only one of these factors: $(r+q)$ , then in order to express both rational expressions with the same common denominator, we multiply numerator and denominator of the second fraction by the factor: $(r-q)$