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Effectus [21]
3 years ago
13

what is the conditional statement, the inverse, converse, and contrapositive of the statement ' Through any three noncollinear p

oints there exists exactly one plane'?
Mathematics
1 answer:
zmey [24]3 years ago
8 0
In in the middle between a and c
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The product of three numbers is -216, but their sum is -18. <br><br> I’ll give 18 points!!!!
sergey [27]
-6 x -6 x -6 = -216
-6 + -6 + -6 = -18
So the answer is negative 6
8 0
3 years ago
Which expression is a factor of 12x2 + 29x – 8?
Contact [7]

Answer:

3x + 8, hope this helps.

4 0
3 years ago
Marcellus sent four faxes to Gem. The first fax took 14 seconds to send, the second fax 19 seconds, the third 16 seconds, and th
Scrat [10]

It took 60 seconds to fax all documents to Gem

Step-by-step explanation:

The simple addition has to be done to solve the given problem

Given

total faxes = 4

Time for fax 1: t_1 = 14\ sec

Time for fax 2: t_2 = 19\ sec

Time for fax 3: t_3 = 16\ sec

Time for fax 4: t_4 = 11\ sec

The total time t will be:

t = t_1+t_2+t_3+t_4\\= 14+19+16+11\\= 60\ sec

Hence,

It took 60 seconds to fax all documents to Gem

Keywords: Time, addition

Learn more about addition at:

  • brainly.com/question/9231234
  • brainly.com/question/9214411

#LearnwithBrainly

8 0
2 years ago
Read 2 more answers
According to a recent​ publication, the mean price of new mobile homes is ​$63 comma 800. Assume a standard deviation of ​$7900.
wolverine [178]

Answer:

a. For n=25, the mean and standard deviation of the prices of the mobile homes all possible sample mean prices are ​$63,800 and ​$1,580​, respectively.

b. For n=50, the mean and standard deviation of the prices of the mobile homes all possible sample mean prices are ​$63,800 and ​$1,117​, respectively.

Step-by-step explanation:

In this case, for each sample size, we have a sampling distribution (a distribution for the population of sample means), with the following parameters:

\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{n}

For n=25 we have:

\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{25}=7,900/5=1,580

The spread of the sampling distribution is always smaller than the population spread of the individuals. The spread is smaller as the sample size increase.

This has the implication that is expected to have more precision in the estimation of the population mean when we use bigger samples than smaller ones.

If n=50, we have:

\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{50}=7,900/7.07=1,117

4 0
3 years ago
Required information An article presents a new method for timing traffic signals in heavily traveled intersections. The effectiv
Natasha2012 [34]

Answer:

652.6-2.01\frac{311.7}{\sqrt{50}}=563.997    

652.6+2.01\frac{311.7}{\sqrt{50}}=741.203    

So on this case the 95% confidence interval would be given by (563.997;741.203)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=652.6 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=311.7 represent the sample standard deviation

n=50 represent the sample size  

Soltuion to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=50-1=49

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,49)".And we see that t_{\alpha/2}=2.01

Now we have everything in order to replace into formula (1):

652.6-2.01\frac{311.7}{\sqrt{50}}=563.997    

652.6+2.01\frac{311.7}{\sqrt{50}}=741.203    

So on this case the 95% confidence interval would be given by (563.997;741.203)    

6 0
3 years ago
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