Find the measure of each angel
1 answer:
<h3>1.</h3>
We will write and solve an equation that expresses the given relation. Let x represent the angle measure. Its complement is (90-x).
... x =(1/4)(90 -x)
Subtract x and simplify
... 0 = (90/4) - (5/4)x
Divide by the coefficient of x, which is -5/4.
... 0 = -18 +x
Add the opposite of the constant.
... 18 = x
The angle is 18°.
<h3>2.</h3>The attachment shows the intersction of road AB with road CD.
<em>Supplementary angles:</em> ∠CXA and ∠CXB; ∠BXC and ∠BXD; ∠DXA and ∠DXB; ∠AXC and ∠AXD.
<em>Complementary angles:</em> none
<em>Vertical angles:</em> ∠AXC and ∠BXD; ∠BXC and ∠AXD.
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a)
the average speed, well it does 10 ft in 1.6 secs, so is simply their quotient, 10/1.6 = 6.25 ft/s on average.
b)
over the horizontal, well, it covered horizontally 9.25 ft in those 1.6 secs, so their quotient is 9.25/1.6 = 5.78125 ft/s on average.
c)
we don't know the vertical distance, but
so, it covered vertically about 3.8 ft in those 1.6 secs, so then 3.8/1.6 = 2.375 ft/s on average