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Usimov [2.4K]
4 years ago
6

Find the measure of each angel

Mathematics
1 answer:
mr_godi [17]4 years ago
4 0
<h3>1.</h3>

We will write and solve an equation that expresses the given relation. Let x represent the angle measure. Its complement is (90-x).

... x =(1/4)(90 -x)

Subtract x and simplify

... 0 = (90/4) - (5/4)x

Divide by the coefficient of x, which is -5/4.

... 0 = -18 +x

Add the opposite of the constant.

... 18 = x

The angle is 18°.

<h3>2.</h3>

The attachment shows the intersction of road AB with road CD.

<em>Supplementary angles:</em> ∠CXA and ∠CXB; ∠BXC and ∠BXD; ∠DXA and ∠DXB; ∠AXC and ∠AXD.

<em>Complementary angles:</em> none

<em>Vertical angles:</em> ∠AXC and ∠BXD; ∠BXC and ∠AXD.

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Step-by-step explanation:

A 45-45-90 traingle is a special traingle.  Let's say one of the leg of the triangle is x. The other one is also x because of the isosocles triangle theorem.  Therefore, using the pytagorean theorem, you find that x^2+x^2=c^2.  2(x)^2=c^2.  You then square root both sides and get c= x√2.  

Therefore, the two legs are x and the hypotenuse is x√2.  x√2=128 because the question says that the hypotenuse is 128.  Solve for x by dividing both sides by √2.  X=128/√2.  You rationalize it by multiplying the numberator and denominator of the fraction by √2.  √2*√2= 2.

X=(128√2)/2= 64√2 cm.

Since X is the leg, the answer would be 64√2

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