1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ganezh [65]
3 years ago
10

Explain how paper chromatography could be used to separate a mixture of different coloured inks

Chemistry
1 answer:
GuDViN [60]3 years ago
3 0

Answer:

Chromatography is a method of separation of materials from a mixture. Paper chromatography is a technique of separation where, paper used as a stationary phase and solvent used to separate the sample used as a mobile phase. The sample is applied over the paper in small quantity. The components of the sample separates in a chromatographic paper due to the movement of solvent. The components of the sample moves with the solvent.

Paper chromatography is a useful technique for ink analysis. Ink consists of several dyes, which can be separated individually. When the ink is exposed to certain solvent mixtures the dyes of the ink dissolves in the mixture. Each ink components acquire distinct distance according to the retention factor. Some inks are water soluble, so the solvent used for separation should be water. Inks which are not water soluble are soluble in other solvents like alcohol.

You might be interested in
What are the parts of an atom, and how are they used to determine an atom’s mass and identity?
Annette [7]

The majority of an atoms' mass comes from the protons and neutrons that make up its nucleus.

4 0
4 years ago
Dichlorine monoxide, Cl2O is sometimes used as a powerful chlorinating agent in research. It can be produced by passing chlorine
Amiraneli [1.4K]

Answer:

% yield =  82.5%

Explanation:

HgO + 2Cl₂ →  HgCl₂ +  Cl₂O

Our reactants are:

  • HgO and Cl₂

Our products are:

  • HgCl₂ +  Cl₂O

We do not have information about moles of reactants, but we do know the theoretical yield and the grams of product, in this case Cl₂O, we have produced.

Percent yield = (Yield produced / Theoretical yield) . 100

Theoretical yield is the mass of product which is produced by sufficent reactant. We replace data:

% yield = (0.71 g/0.86g) . 100 = 82.5%

7 0
3 years ago
Why does ammonia gas diffuse faster than hydrogen chloride gas?
Yakvenalex [24]
The ammonia gas, having a lower molecular weight than the hydrogen chloride, will diffuse faster and travel a greater length of the tube. Consequently, the white ring of ammonium chloride will form much closer to hydrochloric acid end of the tube. Which in conclusion your answer will be D :)
4 0
2 years ago
Calculate the initial molarity of MCHM in the river, assuming that the first part of the river is 7.60 feet deep, 100.0 yards wi
Effectus [21]

Answer:

[MCHM] = 7.52 M

Explanation:

This all about unit conversion

1 feet = 0.3048 meters

1 yard = 0.9144 meters

7.60 feet . 0.3048 = 2.31 meters deep

100 yd . 0.9144 meters = 91.44 meters long and 91.44 meters wide

In the river we have a volume of:

2.31 m . 91.44m . 91.44m = 19314.5  m³

1 dm³ = 1 L

1 dm³ = 0.001 m³

19314.5 m³ / 0.001 m³ = 19314542 L (The final volume of the river)

3.785 L = 1 gallon

In 19314542 L, we have (19314542 / 3.785) = 5102917 gallons

1 gallon = 128 oz

5102917 gallons . 128 = 653173376 oz

1 oz = 28.3495 g

653173376 oz . 28.495 = 1.86x10¹⁰ grams

Molar mass MCHM = 128 g/m

Moles of MCHM = 1.86x10¹⁰ grams / 128 g/m = 145312500 moles

Molarity = mol /L → 145312500 moles / 19314542 L = 7.52 M

7 0
4 years ago
Assume that the complete combustion of one mole of glucose, a monosaccharide, to carbon dioxide and water liberates 2870 kJ2870
Lubov Fominskaja [6]

Answer:

number of moles of the compound \approx 53 mole

Explanation:

Given that:

The total energy liberated = - 2870 kJ  ( here , the negative sign typical implies the release of energy due to the combustion reaction)

The equation of the reaction can be represented as:

\mathbf{C_6H_{12}O_6_{(s)} + 6O_{2(g)} \to 6CO_{2(g)}+6H_2O_{(l)}}

The energy needed to synthesize 1 mole of compound X  = - 54.1 kJ.mol

Thus;

The total energy = numbers of moles of compound × Energy needed to synthesize  1 mole of compound X

Making the numbers of moles of the compound the subject; we have;

numbers of moles of compound = numbers  \ of \  moles  \ of \  compound =  \dfrac{total \ energy }{Energy \  needed  \ to  \ synthesize \   1  \ mole \  of \  compound  \ X}numbers  \ of \  moles  \ of \  compound =  \dfrac{-2870  \ kJ }{-54.1  \ kJ/mol}

number of moles of the compound = 53.04990  mole

number of moles of the compound \approx 53 mole to two significant figure

7 0
4 years ago
Other questions:
  • Compare the solubility of a fatty acid and a fatty acid salt in water. Compare the solubility of a fatty acid and a fatty acid s
    6·1 answer
  • What mass of nitrogen dioxide, NO2, would be produced by the decomposition of 75.0 g of copper (II) nitrate?
    15·1 answer
  • NEED HELP ASAP!!!PLZZ
    12·1 answer
  • Why do you believe knowing how elements and compounds react together is essential in everyday matters?
    10·2 answers
  • What is the maximum mass in grams of NH3 that can be produced by the reaction of of 2.5 g N2 with 2.5 g of H2 via the equation b
    6·1 answer
  • The diagram shows four different locations in an atom. A shaded circle is shown, labeled nucleus. Two small points labeled one a
    13·2 answers
  • How many molecules are there in 2.30 grams of NH3 ?
    5·1 answer
  • 2. How many moles of salt are present in 1.5L of a 5.OM salt water solution?
    5·1 answer
  • Balance the following reaction:<br> C₃H1₂ +<br> 02<br> CO2 +<br> H20
    15·1 answer
  • Fill in the blanks.
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!