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Nana76 [90]
4 years ago
8

Which protists lack cilia and flagella, but can still move around?

Chemistry
1 answer:
timama [110]4 years ago
3 0

Answer: amoebae !

Explanation:

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Balance each reaction and write its reaction quotient, Qc:(a) NO₂Cl(g) ⇄ NO₂(g) + Cl₂(g)
AleksAgata [21]

When we balance the given equation

NO₂Cl(g) ⇄ NO₂(g) + Cl₂(g)

We will get

2NO₂Cl(g) ⇄ 2NO₂(g) + Cl₂(g)

Solution:

Balancing the given equation

NO₂Cl(g) ⇄ NO₂(g) + Cl₂(g)

We have to balance the number of Cl

2NO₂Cl(g) ⇄ NO₂(g) + Cl₂(g)

We have to balance the number of N, O.

2NO₂Cl(g) ⇄ 2NO₂(g) + Cl₂(g)

We will get the balanced equation

2NO₂Cl(g) ⇄ 2NO₂(g) + Cl₂(g)

The reaction quotient will be

    Qc = [product] / [reactant]

     Qc ​= [NO₂(g) + Cl₂(g)] / [NO₂Cl(g)]

To learn more click the given link

brainly.com/question/26694427

#SPJ4

5 0
2 years ago
What is the name of this hydrocarbon
slamgirl [31]

Answer:

the IUPAC name of the following compound is 2,3 dimethyl pentane!

5 0
3 years ago
A microscope containing two or more lenses is an
kicyunya [14]
<span> A compound <span>lens microscope. </span></span>
6 0
3 years ago
A cylinder is filled with 10.0L of gas and a piston is put into it. The initial pressure of the gas is measured to be 96.0kPa. T
Norma-Jean [14]

Answer:

The final pressure of the gas is:- 21.3 kPa

Explanation:

Using Boyle's law  

{P_1}\times {V_1}={P_2}\times {V_2}

Given ,  

V₁ = 10.0 L

V₂ = 45.0 L

P₁ = 96.0 kPa

P₂ = ?

Using above equation as:

{P_1}\times {V_1}={P_2}\times {V_2}

{96.0\ kPa}\times {10.0\ L}={P_2}\times {45.0\ L}

{P_2}=\frac {{96.0}\times {10.0}}{45.0}\ kPa

{P_2}=21.3\ kPa

The final pressure of the gas is:- 21.3 kPa

3 0
3 years ago
This is the chemical formula for carvone (the chemical that gives spearmint its flavor): An organic chemist has determined by me
xz_007 [3.2K]

The given question is incomplete. The complete question is :

This is the chemical formula for carvone (the chemical that gives spearmint its flavor) C_{10}H_{14}O: An organic chemist has determined by measurements that there are 27.3 moles of carbon in a sample of carvone. How many moles of oxygen are in the sample

Answer: 2.73 moles of oxygen are there in the sample.

Explanation:

The chemical formula of carvone is C_{10}H_{14}O.

This means:

When 10 moles of carbon are there in carvone , 1 mole of oxygen is there in carvone

Thus for 27.3 moles of carbon in carvone , \frac{1}{10}\times 27.3=2.73 mole of oxygen is there in carvone.

Thus 2.73 moles of oxygen are there in the sample.

6 0
3 years ago
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