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3 years ago

Help me pls!!!!!!!!!!!

Chemistry

1 answer:

Ludmilka [50]3 years ago

7 0

Answer:

i disagree with seths friend

Explanation:

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When should you read the label on a chemical container?

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Always. You never know what kind of chemical you’re dealing with and how powerful it is.

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Balance C12H22011 → C + H2

svlad2 [7]

Answer:

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3 years ago

Enter a balanced equation for the reaction between solid nickel(II)(II) oxide and carbon monoxide gas that produces solid nickel

velikii [3]

Answer: A balanced equation for the given reaction is $NiO(s) + CO \rightarrow Ni(s) + CO_{2}(g)$ .

Explanation:

The reaction equation will be as follows.

$NiO(s) + CO \rightarrow Ni(s) + CO_{2}(g)$

Number of atoms on the reactant side is as follows.

O = 2
C = 1

Number of atoms on the product side is as follows.

Ni = 1
O = 2
C = 1

Since number of atoms on both the reactant and product sides are equal. Hence, the reaction equation is balanced.

Thus, we can conclude that a balanced equation for the given reaction is $NiO(s) + CO \rightarrow Ni(s) + CO_{2}(g)$ .

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3 years ago

Making jam and dry ice sublimating and becoming a gas are exapleanof what

Natali [406]

Answer:

Sublimation is a phase transition that occurs when a solid changes into a gas — or, as

Explanation:

3 0

3 years ago

How much heat is required to convert 20.0 g of ice at 50.0⁰C to liquid water at 0.0⁰C? The specific heat of ice is 2.06 J/(g∙⁰C)

Alex777 [14]

Answer:

8740 joules are required to convert 20 grams of ice to liquid water.

Explanation:

The amount of heat required ( $Q$ ), measured in joules, to convert ice at -50.0 ºC to liquid water at 0.0 ºC is the sum of sensible heat associated with ice and latent heat of fussion. That is:

$Q = m\cdot [c\cdot (T_{f}-T_{o})+L_{f}]$ (1)

Where:

$m$ - Mass, measured in grams.

$c$ - Specific heat of ice, measured in joules per gram-degree Celsius.

$T_{o}$ , $T_{f}$ - Temperature, measured in degrees Celsius.

$L_{f}$ - Latent heat of fussion, measured in joules per gram.

If we know that $m = 20\,g$ , $c = 2.06\,\frac{J}{g\cdot ^{\circ}C}$ , $T_{f} = 0\,^{\circ}C$ , $T_{o} = -50\,^{\circ}C$ and $L_{f} = 334\,\frac{J}{g }$ , then the amount of heat is:

$Q = (20\,g)\cdot \left\{\left(2.06\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot [0\,^{\circ}C-(-50\,^{\circ}C)]+334\,\frac{J}{g} \right\}$

$Q = 8740\,J$

8740 joules are required to convert 20 grams of ice to liquid water.

3 0

3 years ago