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Annette [7]
2 years ago
9

An unbalanced equation is shown. In this reaction, 200.0 g of FeS2 is burned in 100.0 g of oxygen, and 55.00 g of Fe2O3 is produ

ced.
4FeS2 + 11O2 mc021-1.jpg Fe2O3 + SO2
What is the percent yield of Fe2O3?
Chemistry
1 answer:
Crazy boy [7]2 years ago
3 0
<span>4FeS2 + 11O2 = 2Fe2O3 + 8SO2</span>

Percent yield is calculated as the actual yield divided by the theoretical yield multiplied by 100.

Actual yield = 55 g ( 1 mol / 159.69 g ) = 0.34 mol Fe2O3

To find for the theoretical yield, we first determine the limiting reactant.

100 g O2 ( 1 mol / 32 g) = 3.13 mol O2
200 g FeS2 (1 mol / 119.98g) = 1.67 mol FeS2

Therefore, the limiting reactant is O2.

Theoretical yield = 3.13 mol O2 ( 2 mol Fe2O3 / 11 mol O2 ) = 0.57 mol Fe2O3

Percent yield = (0.34 mol / 0.57 mol) x 100 = 59.74%
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Is a forward or reverse reaction favored?
Alex Ar [27]

Answer:

(a) CH_3COOH \rightleftharpoons CH_3COO^-+ H^+: reverse reaction is favored.

(b) AgCl \rightleftharpoons Ag^+ + Cl^-: reverse reaction is favored.

(c) Al(OH)_3 \rightleftharpoons Al^{3+} + 3OH^-: reverse reaction is favored.

(d) A+B\rightleftharpoons C: forward reaction is favored.

Explanation:

Hello,

(a) CH_3COOH \rightleftharpoons CH_3COO^-+ H^+:

In this case, since the Ka is lower than 1, we infer the reverse reaction is favored since the reactant (acetic acid) will tend to have a higher concentration.

(b) AgCl \rightleftharpoons Ag^+ + Cl^-:

In this case, since the Ka is lower than 1, we infer the reverse reaction is favored since the reactant (silver chloride) will tend to have a higher concentration.

(c) Al(OH)_3 \rightleftharpoons Al^{3+} + 3OH^-

In this case, since the Ka is lower than 1, we infer the reverse reaction is favored since the reactant (aluminium hydroxide) will tend to have a higher concentration.

(d) A+B\rightleftharpoons C

In this case, since the Ka is greater than 1, we infer the forward reaction is favored since the product (C) will tend to have a higher concentration.

Regards.

6 0
2 years ago
A 25.0 mL sample of sulfuric acid is completely neutralized by adding 32.8 mL of 0.116 mol/L ammonia solution. Ammonium sulfate
Paul [167]

Answer:

0.08 mol L-1

Explanation:

Sulfuric acid Formula: H2SO4

Ammonia Formula: NH3

Ammonium sulfate Formula: (NH₄)₂SO₄

H2SO4 + 2NH3 = 2NH4+ + SO4 2-

H2SO4 + 2NH3 = (NH₄)₂SO₄

H2SO4 = (1/2)x (32.8 x 10^-3 L x 0.116 mol L-1)/25 x 10^-3 L

= 0.08 mol L-1

7 0
2 years ago
What is the wave speed if the wave length is 8 and the frequency is 20
PilotLPTM [1.2K]

Answer:

160m/s

Explanation:

To find V Use the following formula V= F*W

V= Velocity F= Frequency W= Wavelength

V=20*8

=160m/s

4 0
3 years ago
How many molecules are in 4.50 moles of H2O?
alisha [4.7K]
C can be the only correct answer - 6.023 x 10^23 is the amount of molecules in a mol of an element. 4.5 x 6.023 x 10^23 can not equal anything but C.

4.5 x 6.023 x 10^23 = 2.71035 x 10^24
8 0
3 years ago
Read 2 more answers
A 47.0 mL aliquot of a 0.400 M stock solution must be diluted to 0.100 M. Assuming the volumes are additive, how much water shou
mel-nik [20]

Answer:

The answer is 0.188L

Explanation:

I did the problem on paper and put the answer on the pictures. I'm sorry if I didn't explain it well but I hope I helped.

5 0
3 years ago
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