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Alla [95]
2 years ago
15

You have a 5-liter container with 1.30 x 1024 molecules of ammonia gas (NH3) at STP.

Chemistry
1 answer:
bogdanovich [222]2 years ago
6 0

Answer:

3). 1.30 × 10^(24) molecules

Explanation:

From avogadro's law which state that equal volume of all gases at the same temperature and pressure contain the same number of molecules.

We can relate it to this question as;

V₁/n₁ = V₂/n₂

Where;

V₁ is initial volume

n₁ is initial number of molecules

V₂ is final volume

n₂ is final number of molecules

Thus at STP, we have V₁ = V₂ and as such Plugging in the relevant values gives;

5/(1.30 x 10^(24)) = 5/n₂

n₂ = 1.30 x 10^(24) molecules

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What are atoms?
user100 [1]

Answer:

The smallest particle of a chemical element can be defined as an atom.

Explanation:

The number of protons in one atom of an element determines the atom's identity, and the number of electrons determines its electrical charge.

a single electron or one of two or more electrons in the outer shell of an atom that is responsible for the chemical properties of the atom is known as valence electrons.

An atom's reactivity is its tendency to lose or gain electrons. ... This is because they have one outer electron and losing it gives them the stability of a outer electron shell as the next level... The reactivities of elements can be predicted by periodic trends.

7 0
3 years ago
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Determine the number of moles in 382.5g of CO-2
exis [7]

Answer: 8.691 mols of CO₂

Explanation:

To find the number of moles in a given grams, you want to use the molar mass.

Let's first find the molar mass of CO₂.

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Oxygen's molar mass is 15.999 g/mol

To find molar mass of CO₂, we want to add up the molar mass of carbon and oxygen. Remember, there are 2 Oxygens so we need to mulitply that by 2.

12.011+2(15.999)=44.009 g/mol

Now that we have molar mass, we can convert 382.5 g to mols.

382.5g*\frac{1 mol}{44.009g} =8.691 mol

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5 0
3 years ago
At 35.0°c and 3.00 atm pressure, a gas has a volume of 1.40 l. what pressure does the gas have at 0.00°c and a volume of 0.950 l
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Answer : The pressure of gas will be, 3.918 atm and the combined gas law is used for this problem.

Solution :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 3 atm

P_2 = final pressure of gas = ?

V_1 = initial volume of gas = 1.40 L

V_2 = final volume of gas = 0.950 L

T_1 = initial temperature of gas = 35^oC=273+35=308K

T_2 = final temperature of gas = 0^oC=273+0=273K

Now put all the given values in the above equation, we get the final pressure of gas.

\frac{3atm\times 1.40L}{308K}=\frac{P_2\times 0.950L}{273K}

P_2=3.918atm

Therefore, the pressure of gas will be, 3.918 atm and the combined gas law is used for this problem.

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3 years ago
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