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Sindrei [870]
3 years ago
7

An equation is given. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal places w

here appropriate. If there is no solution, enter NO SOLUTION.) 2 sin(2θ) = 1 (a) Find all solutions of the equation. θ = (b) Find the solutions in the interval [0, 2π). θ =
Mathematics
1 answer:
uranmaximum [27]3 years ago
8 0

Answer:

a) θ = 15° b) θ = 15°, 165°

Step-by-step explanation:

a) Given the equation 2 sin(2θ) = 1

sin(2θ) = 1/2

(2θ) = arcsin(1/2)

2θ = 30°

θ = 15°

b) To find all the solutions between 0 and 2π, we will make reference to the quadrant.

Sinθ is positive in the first and second quadrant.

In the first quadrant, θ = 15°

In the second quadrant, θ = 180°-15°

= 165°

The solutions between 0 and 2π are 15° and 165°

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Solve:<br><br> a = 0<br><br> a = 8<br><br> no solution
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lisov135 [29]

Answer:

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Step-by-step explanation:

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netineya [11]

Answer:

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if its right can u pls mark as brainliest?

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