..............................................................help me

Mathematics

1 answer:

NeTakaya3 years ago

6 0

Answer:

8 & 2

Step-by-step explanation:

hope it helps u.

and best of luck for ur exam.

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An envelope is 4 cm longer than it is wide. the area is 96 square centimeters. find the length and width.

Dennis_Churaev [7]

<span>So, L*W=A Because it is 4 cm longer, L=W+4 Because the area is 96, LW=96 Substitute to get W(W+4)=96 Multiply it out. W^2+4W-96=0 By solving the quadratic, W+12(W-8)=0 so either W+12 or W-8 is zero. The width must be positive, so the width is 8. Therefore the length is 12.

Hope this helps.</span>

4 0

3 years ago

Consider the line y=4x-4.

erica [24]

9514 1404 393

Answer:

parallel: y = 4x -6
perpendicular: y = -1/4x +27/4

Step-by-step explanation:

If we want the new line to be written in slope-intercept form, we need to find the new value of the y-intercept. The equation of the line is ...

y = mx +b . . . . . . . for slope m and y-intercept b

Solving for b gives ...

b = y -mx . . . . . . . subtract mx from both sides.

The values of x and y come from the point we want the line to pass through. The value of m will be the same for the parallel line as for the given line: 4. For the perpendicular line, it will be the opposite reciprocal of this: -1/4.

<u>Parallel line</u>

b = 6 -4(3) = 6 -12 = -6

y = 4x -6

Perpendicular line

b = 6 -(-1/4)(3) = 6 +3/4 = 27/4

y = -1/4x +27/4