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vfiekz [6]
3 years ago
6

Is 5361 divisible by three how do you know just by looking at it

Mathematics
1 answer:
lakkis [162]3 years ago
5 0

Answer and explanation

You add all of the digits together a see if it is divisible by 3 sooooo...........

5+3+6+1=15/3=5

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How do you write the proportion 9:36 = 10:40 using words ?
valentina_108 [34]

9 is to 36 as 10 is to 40 -is how you should write the proportion 9:36 = 10:40 using words.

8 0
3 years ago
For which function is the domain
Anettt [7]

Answer:

D. y=\sqrt{x}

Step-by-step explanation:

A square root can't be evaluated if the number we want to find the square of  is nagative.

3 0
3 years ago
Which are these are polygons
oee [108]
<h3>3 Answers: B, C, F</h3>

Each of these are closed figures formed by straight line segments. Think of fencing in an area (not necessarily a rectangle) using various straight fence sections. The length of each section does not have to be the same.

Side notes:

  • Choice A is not a polygon because the figure is not closed.
  • Choice D is not a polygon because it is not composed of line segments only. Choice D is an ellipse instead.
  • Choice E is not a polygon due to the curved portion.
3 0
3 years ago
1
Papessa [141]

Answer:

d = 10/72

Step-by-step explanation:

c and d vary inversely

c = k/d

Where,

k = constant of proportionality

d = 2/9 when c = 5

c = k/d

5 = k ÷ 2/9

5 = k × 9/2

5 = 9k/2

Cross product

5*2 = 9k

10 = 9k

k = 10/9

c = k/d

c = 10/9 ÷ d

c = 10/9 × 1/d

c = 10/9d

find d when c = 8

c = 10/9d

8 = 10/9d

Cross product

8*9d = 10

72d = 10

d = 10/72

8 0
3 years ago
Practice Writing Composite Functions Given: f(x) = x - 7 and h(x) = 2x + 3 Write the rule for h(f(x)).
Setler79 [48]

Answer:

<h2>h(f(x)) = 2x - 11</h2>

Step-by-step explanation:

f(x) = x - 7

h(x) = 2x + 3

To find h(f(x)) substitute f(x) into h(x) that's replace every x in h(x) by f(x)

That's

h(f(x)) = 2(x - 7) + 3

h(f(x)) = 2x - 14 + 3

We have the final answer as

<h3>h(f(x)) = 2x - 11</h3>

Hope this helps you

6 0
3 years ago
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