All categories

3 years ago

Simplify the following expressions without using a calculator

Mathematics

1 answer:

wolverine [178]3 years ago

6 0

Answer:

13x^3y^4 i am not sure

You might be interested in

Professor Stache awarded 500 certificates, some for math, and some for science. Girls won 2/3 of the math certificates and 1/2 o

wariber [46]

Answer:

Step-by-step explanation:

Given:

Total certificates = 500
Math = m
Science = s

Equations

m+s = 500 ⇒ s = 500 - m

Girls who won certificates:

2/3m = 50 + 3/2*1/2s
2/3m = 50 + 3/4s

Multiply both sides by 12 to clear fractions

8m = 600 + 9s

Substitute s

8m = 600 + 9(500 - m)
8m = 600 + 4500 - 9m
17m = 5100
m = 5100/17
m =300

Girls who won math:

2/3*300 = 200

5 0

4 years ago

What is Cube root of 125 x Superscript 12? A. 5x2 B. 5x4 C. 25x2 D. 25x4

nasty-shy [4]

<h3>Answer: B) 5x^4</h3>

==============================================

Work Shown:

125 = 5*5*5 = (5)^3

x^12 = (x^4)*(x^4)*(x^4) = (x^4)^3

125x^12 = (5x^4)^3

$\large \sqrt[3]{125x^{12}} = \left(125x^{12}\right)^{1/3}$

$\large \sqrt[3]{125x^{12}} = \left((5x^4)^3\right)^{1/3}$

$\large \sqrt[3]{125x^{12}} = (5x^4)^{3*(1/3)}$

$\large \sqrt[3]{125x^{12}} = (5x^4)^{1}$

$\large \sqrt[3]{125x^{12}} = \textbf{5x}^{\textbf{4}}$

8 0

3 years ago

Read 2 more answers

HELP DUE IN 15 MINS!

boyakko [2]

Answer:

r = $2\sqrt{5}$

$(x - 3)^{2} + ( y - 2)^{2} = 20$

Is this a live test question or a homework question?

Step-by-step explanation:

the radius is the distance between (3, 2) and (5, -2)

$r^{2}$ = ${(3 - 5)^{2} + (2 + 2)^{2} }$

= $(-2)^{2} + 4^{2}$

= 4 + 16 = 20

r = $\sqrt{20 } = 2\sqrt{5}$

Equation of circle: $(x - 3)^{2} + ( y - 2)^{2} = 20$

8 0

3 years ago

Read 2 more answers

For funcitons f(x)=2x+3 and g(x)=-3x-2, please find (f∘g)(-1)

ratelena [41]

Answer:

$\displaystyle (f\circ g)(-1) = 5$

Step-by-step explanation:

We are given the two functions:
$\displaystyle f(x) = 2x + 3\text{ and } g(x) = -3x - 2$

And we want to find:
$\displaystyle (f\circ g)(-1)$

Recall that this is equivalent to:
$\displaystyle (f\circ g)(-1) = f(g(-1))$

Hence, find g(-1):
$\displaystyle \begin{aligned} g(x) & = -3x - 2\\ \\ g(-1) & = -3(-1) - 2\\ \\ & = (3) - 2 \\ \\ & = 1 \end{aligned}$

Substitute:
$\displaystyle f(g(-1)) = f(1)$

Find f(1):

$\displaystyle \begin{aligned} f(x) & = 2x+ 3 \\ \\ f(1) & = 2(1) + 3 \\ \\ & = 5\end{aligned}$

In conclusion:
$\displaystyle (f\circ g)(-1) = 5$

5 0

3 years ago

PLEASE ANSWER THIS QUESTION RIGHT PLEASE Devante Has a lunch account in the school cafeteria. His starting balance at the beginn

Gnoma [55]

Answer:

C) The amount of money in his lunch account

Step-by-step explanation:

6 0

3 years ago