Question

Write the equation of a line that is perpendicular to -2/7x+9 that passes through the point (4, -6)

Answer 1

Answer:

7y + 2x + 34 = 0

Step-by-step explanation:

The gradient for perpendicular, m = -2/7

The formular equation, y - y1 = m(x - x1)

The equation of line through (4, -6) is:

y - (-6) = -2/7(x - 4)

y + 6 = -2x/7 + 8/7

7y + 42 + 2x - 8 = 0

7y + 2x + 34 = 0

Answer 2

Answer:

the desired equation is y = (-7/2)x - 8

Step-by-step explanation:

Don't you mean y = -2/7x+9, or y = (2/7)x+9?   Any line perpendicular to this line has a slope of -7/2, the negative reciprocal of (2/7).

Start with the slope-intercept formula:

y = mx + b.  Substitute -6 for  y, 4 for x and -7/2 for m.  Then we have

-6 = (-7/2)(4) + b.   This reduces to -6 = -14 + b, so that b must be -8.

Thus, the desired equation is y = (-7/2)x - 8