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zvonat [6]
3 years ago
14

Let logba=3 logbc=2 logbd=5 what is the value of logba^3d^4/c^2

Mathematics
1 answer:
myrzilka [38]3 years ago
8 0
Use:\\\log_ax+\log_ay=\log_a(xy)\\\\\log_ax-\log_ay=\log_a\dfrac{x}{y}\\\\\log_ax^n=n\cdot\log_ax

\log_ba=3;\ \log_bc=2;\ \log_bd=5

\log_b\dfrac{a^3d^4}{c^2}=\log_b(a^3d^4)-\log_bc^2=\log_ba^3+\log_bd^4-\log_bc^2\\\\=3\log_ba+4\log_bd-2\log_bc=3\cdot3+4\cdot5-2\cdot2=9+20-4=25

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