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3 years ago

Let logba=3 logbc=2 logbd=5 what is the value of logba^3d^4/c^2

1 answer:

8 0

$Use:\\\log_ax+\log_ay=\log_a(xy)\\\\\log_ax-\log_ay=\log_a\dfrac{x}{y}\\\\\log_ax^n=n\cdot\log_ax$

$\log_ba=3;\ \log_bc=2;\ \log_bd=5$

$\log_b\dfrac{a^3d^4}{c^2}=\log_b(a^3d^4)-\log_bc^2=\log_ba^3+\log_bd^4-\log_bc^2\\\\=3\log_ba+4\log_bd-2\log_bc=3\cdot3+4\cdot5-2\cdot2=9+20-4=25$

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2. Solve the following 10/12 - 4/3

Mama L [17]

The answer is $-\frac{1}{2}$

First you must change the fractions so that they have like denominators.

$\frac{10}{12} -\frac{16}{12}$

Then you subtract the fractions.

$-\frac{6}{12}$

Finally, you need to simplify the answer.

$-\frac{1}{2}$

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3 years ago

Emily had 75 buttons she gave 15 away to jake what persent of buttons did she give away

erma4kov [3.2K]

Answer:

20%

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4 years ago

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4 years ago

Find the maximum value of the function for the polygonal convex set determined by the given system of inequalities.

V125BC [204]

Answer:

A. at (8,7) the maximum value is 98

Step-by-step explanation:

First draw the region, that is bounded by all

inequalities. This is the triangle with vertices

(6,1), (2,5) and (8,7).

Now you can see where the line f(x,y)=7x+6y

intersect this region. The maximum value will be

at endpoints of this region:

• at (6,1), f(6,1)=7-6+6-1=42+6=48;

at (2,5), f(2,5)=7·2+6.5=14+30=44;

• at (8,7), f(8,7)=7.8+6-7=56+42=98.

Thus, the maximum value of the function is 98 at

the point (8,7).

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2 years ago

Eddy MS plans to collect more than 3,000 can of food to donate to the EG Food Bank. So far, 500 can have been collected. WRITE a

katrin2010 [14]

Answer:

The in equality representing the number of can school can collect each day is $500+5x\geq 3000$ .

Eddy MS school has to collect at least 500 cans in each day.

Step-by-step explanation:

Number of cans Eddy has = 500

Number of days left = 5

Target to achieve = 3000

Let number of cans which can be collected in each day be 'x'.

Now we know that;

Number of can he has plus number of can which can be collected in each day multiplied with number of days left should be greater than or equal to 3000

Framing in equation form we get;

$500+5x\geq 3000$

Hence, The in equality representing the number of can school can collect each day is $500+5x\geq 3000$ .

Solving the same we get;

$500+5x\geq 3000$ .

Subtracting Both side with 500 using Subtraction property for Inequality we get;

$500+5x-500\geq 3000-500\\\\5x\geq 2500$

Now Dividing both side by 5 using Division property of Inequality we get;

$\frac{5x}{5}\geq\frac{2500}{5}\\\\x\geq 500$

Hence Eddy MS school has to collect at least 500 cans in each day.

7 0

3 years ago