I believe h would be correct
Answer:
1. B
3. C
4. B
5. What r the angles?
Step-by-step explanation:
Sry... I dont think I'm able to do #2 bc I'm only in Algebra I but there u go ;)
I'm assuming they are equivalent...
![5m + 1 = 3m + 7](https://tex.z-dn.net/?f=5m%20%2B%201%20%3D%203m%20%2B%207)
Solve for m and get 3.
~~
I hope that helps you out!!
Any more questions, please feel free to ask me and I will gladly help you out!!
~Zoey
Answer:
The interval from the sample of size 400 will be approximately <u>One -half as wide</u> as the interval from the sample of size 100
Step-by-step explanation:
From the question we are told the confidence level is 95% , hence the level of significance is
=>
Generally from the normal distribution table the critical value of
is
Generally the 95% confidence interval is dependent on the value of the margin of error at a constant sample mean or sample proportion
Generally the margin of error is mathematically represented as
Here assume that
is constant so
![E = \frac{k}{\sqrt{n} }](https://tex.z-dn.net/?f=E%20%3D%20%20%5Cfrac%7Bk%7D%7B%5Csqrt%7Bn%7D%20%7D)
=> ![E \sqrt{n} = K](https://tex.z-dn.net/?f=E%20%5Csqrt%7Bn%7D%20%3D%20K)
=> ![E_1 \sqrt{n}_1 = E_2 \sqrt{n}_2](https://tex.z-dn.net/?f=E_1%20%5Csqrt%7Bn%7D_1%20%3D%20%20E_2%20%5Csqrt%7Bn%7D_2)
So let
and ![n_2 = 100](https://tex.z-dn.net/?f=n_2%20%3D%20%20100)
=> ![E_1 \sqrt{400} = E_2 \sqrt{100}](https://tex.z-dn.net/?f=E_1%20%5Csqrt%7B400%7D%20%3D%20%20E_2%20%5Csqrt%7B100%7D)
=> ![E_1 = \frac{\sqrt{100} }{\sqrt{400} } E_2](https://tex.z-dn.net/?f=E_1%20%3D%20%20%5Cfrac%7B%5Csqrt%7B100%7D%20%7D%7B%5Csqrt%7B400%7D%20%7D%20E_2)
=> ![E_1 = \frac{1}{2 } E_2](https://tex.z-dn.net/?f=E_1%20%3D%20%20%5Cfrac%7B1%7D%7B2%20%7D%20E_2)
So From this we see that the confidence interval for a sample size of 400 will be half that with a sample size of 100
X32 but 32 is the smaller numbers