Question

In a club there is 13 women and 8 men. A committee of 9 women and 4 men is to be chosen. How many different ways are there to select the committee?
A. 50,050 ways
B. 3,744 ways
C. 273 ways
D. 34 ways​

Answer 1

Answer:

The total number of ways to select 9 women and 4 men for the committee is 50,050.

Step-by-step explanation:

The club has 13 female members and 8 male members.

The committee to be formed must have 9 female members and 4 male members.

The possible number of ways to select 9 female from 13 females is:

$n(F)={13\choose 9}=\frac{13!}{9!(13-9)!}=715$

The possible number of ways to select 4 male from 8 males is:

$n(M)={8\choose 4}=\frac{8!}{4!(8-4)!}=70$

Compute the possible total number of ways to select 9 women and 4 men for the committee as follows:

Total number of ways to select 9 women and 4 men = n (F) × n (M)

                                                                                       $=715\times70\\=50050$

Thus, the total number of ways to select 9 women and 4 men for the committee is 50,050.