V=(4/3)pir^2
c=2pir
12=2pir
divide 2
6=pir
divide by pi
6/pi=r
sub for r
V=(4/3)pi(6/pi)^2
V=(4/3)pi(36/(pi^2))
V=(4/3)(36/pi)
V=144/(3pi)
V=48/pi
aprox pi=3.141592
V=15.2788777155
V=15.28 in^3
We can solve this problem by first solving for the total
volume of the cube. The formula for volume of cube is given as:
V cube = s^3
Where s is the length of one side which is equivalent to
2 inches. Therefore:
V cube = (2 inches)^3
V cube = 8 cubic inch
Assuming that all the pebble fills the cube without any
spaces, then the total weight of the pebbles in the cube would simply be:
Total weight = 0.5 lb per cubic inch * 8 cubic inch
Total weight = 4 lb
Therefore, the total weight of the pebbles in the cube is <u>4
lbs</u>.
6 ft 10 in + 8 ft 9 in = 15 ft 7 in
add the inches first and then subtract 12 from the 19 because 12 inches equals 1 foot then add 6+8+1=15 ft don't forget to include the 7 inches in your answer
Answer:
f(x)^-1=x+12
Step-by-step explanation:
f(x)=x-12
y=x-12
x=y-12
y=x+12
f(x)^-1=x+12
Hope it helps.
D. 226.08cm^2
Since we are finding the combined area of the two bases of the cylinder, we are adding the area of the first base with the second base. The formula for the base of a cylinder is pi x r^2, since it is a circle. Since the bases are the same, we can rewrite this as 2pi x r^2.
Since the diameter is 12cm and r = 1/2 diameter, r = 6cm.
Thus, A = 2(3.1415)(6)^2 = 226.08cm^2
