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igor_vitrenko [27]
3 years ago
12

At room temperature what is the strength of the electric field in a 12-gauge copper wire (diameter 2.05 mm that is needed to cau

se a 2.75 a current to flow?
Physics
1 answer:
Dima020 [189]3 years ago
6 0
Electric field strength = resistivity of copper x current density
where
p= 1.72 x 10^-8 <span>ohm meter
diameter = 2.05mm=.00205 m
current = 2.75 A
</span>get first the current density:
current density = current/ cross section area
find the cross section area
cross section area = pi.(d/2)^2;  
cross section = 3.3 006x10-6 m^2
substitute the values 
current density = 2.75A/3.3006x 10-6m^2
current density=35.55 x1 0^2 A/m^2
Electric field stregnth =1.72 x 10^-8 ohm meter x 35.55 x10^2 A/m^2
Electric field stregnth= 46.415 Volts/m

The electric field strength of copper is 46.415 V/m.


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Perpendicular to the surface

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Given the two definitions, equipotential lines are always perpendicular to the electric field lines. Therefore, in this problem, the direction of the electric field is perpendicular to the spherical equipotential surface.

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A force of 960 newtons stretches a spring 4 meters. A mass of 60 kilograms is attached to the end of the spring and is initially
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Now initially

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