Aware is 3(A) I hope this helps
Answer:
F = -6472.9 N
F= -6.47 kN
Explanation:
First of all you have to convert the data to SI units
so for the velocity you have :
Vi = 43km/h *(1000m/1km)*(1h/3600s) ---> using conversion factors
Vi= 11.9444 m/s
dX : distance the passanger moves
dX = 54cm*(1m/100cm) --> using conversion factors
dX = 0.54 m
Now to calculate the force we are going to use the sum of focers equals to mass for acceleration:
Sum F = m*a
We have to find a so we are going to use the velocity's formula as follows to solve a:
Vf ^2 = Vi^2 +2*a*dX
Vf=0 --> the passenger does not move after the airbag inflates.
a= -(Vi^2)/(2*dX)
you solve de acceleration with the data you hae and you will find
a = -132.1 m/ s^2
Now you can solve the Sum F equation
Sum F = 49 Kg * (-132.1 m/s^2)
F = -6472.9 N
F= -6.47 kN
The tilt of Earth's axis hope this helps
Answer:
57.6
Explanation:
"Significant figures" refer to figures that have an actual contribution to a <em>number's value.</em>
They refer to all digits<u> except those with</u><em><u> </u></em><em><u>"leading zero,"</u></em> which means having a zero digit before a specific number. For example, in the number 0234, the significant figures are<em> 234. </em>
The rule for adding and subtracting significant figures is to <em>round off the answer to the least number of decimal places</em>. However, when it comes to multiplying and dividing significant figures, you have<em> round off the answer to the least number of significant digits.</em>
<u>Let's solve.</u>
21.4
+15
17.17
<u> 4.003</u>
57.573
Let's now round off to the<em> least number of decimal places</em>, which is the <em>tenths. </em>Since 0.5 is followed by a number greater than 5, we have to round it off to 6. Therefore, the answer is: 57.6
In the process of finding an image with a lens, three basic lines are usually drawn, the lines are as follows:
LINE ONE: This line represents the ray that leaves the object and travels towards the center of the lens. This line is usually undeflected and it travels through a straight line.
LINE TWO: This line represents the ray which travels from the object parallel to the axis of the lens. The line is deflected in such a way that it passes through the focal point of the lens.
LINE THREE: This line represents the ray that travels from the object and which passes through the focal point on the near side prior to getting to the lens. This line is deflected in such a way that it travels parallel to the axis. <span />