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Sophie [7]
4 years ago
8

If A > B, under what condition is |A-BI=|A|- IB|? a. Vectors A and B are in opposite directions b. Vectors A and B are in the

same direction. c. The statement is never true. d. Vectors A and B are in perpendicular directions. e. The statement is always true.

Physics
1 answer:
kupik [55]4 years ago
5 0

Answer:

b) Vectors A and B are in the same direction.

Explanation:

To understand this problem we will say that vector A has a magnitude of 5 units and vector B a magnitude of 3 units. In the subtraction of vectors the initial parts of vectors always bind together. And the vector resulting from the subtraction is traced from the end of the second vector (B) to the end of the first vector (A).

The length of the resultant vector will be 5 - 3 = 2

In the attached image, we analyze case a), b), and d)

For a)

As we can see in the attached image the resultant vector has a length of 8 units.

For d)

As we can see in the attached image the resultant vector has a length of 5.83 units.

For b)

The resultant vector has a length of 2 units.

Therefore the case given in b) is true

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A rubber bullet of mass m=0.025\,\mathrm{kg}m=0.025kg traveling at velocity v_0 = 50\,\mathrm{m/s}v 0 ​ =50m/s hits an iron bloc
Pavel [41]

Answer: 0.001 m

Explanation:

In order to get the máximum height reached by the iron block, we can use the energy conservation principle, as all the kinetic energy impressed upon the iron blck by the rubber bullet during the collision, becomes gravitational potential energy, as follows:

½ m v2 = m. g. h (1)

We don´t know the value of v, but if we look to the collision, and we asume no external forces act during it, the total momentum must be conserved.

The initial momentum, as the block is at rest, is just the one due to the rubber bullet:

P1 = mb . vb = 0.025 kg. 50 m/s = 1.25 kg. m/s

The final momemtum, is just the sum of the one due to the bullet (after being bounced back) and the one for the iron block:

P2 = mb . vfb  + mib . vib= 0.025 Kg. (-35 m/s) + 15 Kg.vib

As we have already said, P1 = P2, so we can write the following equation:

0.025 Kg. (-35 m/s) + 15 Kg. vib = 1.25 Kg. m/s.

Solving for vib, we have:

vib = 0.14 m/s

Now, we can replace this value in the equation (1) above:

½ . 15 Kg. (0.14)2  (m/s)2 = 15 Kg. 9.8 m/s2. H

Solving for H, we have:

H = 0.001 m

3 0
3 years ago
I just need someone to check my answer!
Crazy boy [7]

That’s actually correct!! Good luck with the test

7 0
3 years ago
A 200-kg object has a 50-Newton rightward net force being applied to it. What is the magnitude of the rightward acceleration on
katovenus [111]
The formula for acceleration is force divided by mass.

Force = 50 N

Mass = 200 kg

Acceleration = ???

\frac{50}{200} = \frac{1}{4}

\frac{1}{4} = 0.25

~~

Acceleration = 0.25 m/s²

~~

Next time use, f = ma in a triangle,

F

M A

~~

I hope that helps you out!!

Any more questions, please feel free to ask me and I will gladly help you out!!

~Zoey
8 0
3 years ago
The frequency is slowly increased. Once it passes the critical value fb, the student hears the ball bounce. There is now enough
vitfil [10]

Answer: g = acceleration = A*w^2 = A*(2*pi*fb)^2.

Explanation:

The ball bounces when the acceleration of the ball exceeds that of gravity. If A and fb are measured at that point, g = acceleration = A*w^2 = A*(2*pi*fb)^2.

3 0
3 years ago
As light slows down, it bends or refracts. The index of refraction helps predict the amount of bending. How are the speed of lig
Eduardwww [97]
When light changes the medium it travels through it also changes speed. The speed in medium is given by formula:
v_{medium} = \frac{c}{ n_{medium} }

Rearranging formual gives:
n_{medium} = \frac{c}{ v_{medium} }

From this formula we can make conclusion that index of refraction is inversely proportional to speed of light in medium. This means that greater speed gives smaller index of refraction.
8 0
4 years ago
Read 2 more answers
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