Answer:
μ = 0.692
Explanation:
In order to solve this problem, we must make a free body diagram and include the respective forces acting on the body. Similarly, deduce the respective equations according to the conditions of the problem and the directions of the forces.
Attached is an image with the respective forces:
A summation of forces on the Y-axis is performed equal to zero, in order to determine the normal force N. this summation is equal to zero since there is no movement on the Y-axis.
Since the body moves at a constant speed, there is no acceleration so the sum of forces on the X-axis must be equal to zero.
The frictional force is defined as the product of the coefficient of friction by the normal force. In this way, we can calculate the coefficient of friction.
The process of solving this problem can be seen in the attached image.
Answer:
The frog's horizontal velocity is 0.2 m/s.
Explanation:
To solve this problem, we must first remember what velocity is and how we solve for it. Velocity can be solved for using the formula x/t, where x represents horizontal distance and t represents time (in seconds), that it takes to travel this distance. If we plug in the given numbers for these variables and solve, we get the following:
v = x/t
v = 0.8m/4s
v = 0.2 m/s
Therefore, the correct answer is 0.2 m/s. We can verify that these units are correct because the formula calls for distance divided by time, so meters per second is a sensible answer.
Hope this helps!
Answer:
0.5849Weber
Explanation:
The formula for calculating the magnetic flus is expressed as:
Given
The magnitude of the magnetic field B = 3.35T
Area of the loop = πr² = 3.14(0.24)² = 0.180864m²
angle of the wire loop θ = 15.1°
Substitute the given values into the formula:
Hence the magnetic flux Φ through the loop is 0.5849Weber
Answer:
The answer to your question is:
a) 2.7 m/s²
b) -3.6 m/s²
Explanation:
Data
mass of the toolbox = 3.2 kg
a = ?
F = 40 N and F = 20 N
g = 9.81 m/s²
Formula
Second law of motion = F = ma
a + g = F / m
a = F/m - g
a) a = 40/3.2 - 9.81
a = 2.69 ≈ 2.7 m/s² positive up
b) a = 20/ 3.2 - 9.81
a = 6.25 - 9.81
= - 3.56 ≈ - 3.6 m/s² negative down
The minimum is 3 Newton, when the two forces act in opposite directions.
