Answer:
Therefore,
The current through the battery is 10.4 Ampere.
Explanation:
Given:
V = 12 V  Battery
Connection is Parallel,
R₁ = 12 Ω 
R₂ = 3 Ω 
R₃ = 5 Ω 
R₄ = 4 Ω 
Let I₁, I₂, I₃, I₄ be the current passing through R₁ ,R₂, R₃, R₄  resistors
To Find:
I =? (current through the battery)
Solution:
As Connection is Parallel Voltage Remain SAME through resistors
Bu Ohm's Law we have

So current through R₁

Substituting the values we get

Similarly, for current through R₂, R₃, R₄,



Now in Parallel Connection we have,

Substituting the values we get

Therefore,
The current through the battery is 10.4 Ampere.