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3 years ago

There are 26.2 miles in a marathon.write the number of miles using fraction

1 answer:

3 0

You can write it in two types of fractions:
1) ur answer will be 26 and 2/10 which can be simplified to 26 and 1/5
2) ur answer will be 262/10 which can be simplified to 131/5
The first is the more recommended way of writing your answers.

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a top athlete sprinting has a power of 1700W the average person running has a power of 1000 W how powerful do u think you are? w

maks197457 [2]

I really dont understand what the W means... But i can definately tell you this: I am a former rythmic gymnast who trained for 5 years, and in gym, i am always first place. True facts

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3 years ago

Please help I still do not understand these questions

solniwko [45]

Answer:

m = 2/5

Step-by-step explanation:

easy

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2 years ago

I need help with number 9

ch4aika [34]

Answer:

Step-by-step explanation:

We can safely assume we are dealing with an arithmetic scale because the type of scale isn't mentioned anywhere. The more right a point is on the scale, the higher its value is. We are given two points of the scale: 3 and 4. Because the scale is arithmetic, we know that 3.8 must lie on 4/5s of the length between 3 and 4 to the right of 3, which is exactly where point D is.

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3 years ago

A teacher was interested in knowing the amount of physical activity that his students were engaged in daily. He randomly sampled

klasskru [66]

Answer:

The standard error of the mean is 4.5.

Step-by-step explanation:

As we don't know the standard deviation of the population, we can estimate the standard error of the mean from the standard deviation of the sample as:

$\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}$

The sample is [30mins, 40 mins, 60 mins, 80 mins, 20 mins, 85 mins]. The size of the sample is n=6.

The mean of the sample is:

$\bar{x}=\frac{1}n} \sum x_i =\frac{30+40+60+80+20+85}{6}=52.5$

The standard deviation of the sample is calculated as:

$s=\sqrt{\frac{1}{n-1}\sum (x_i-\bar x)^2} \\\\ s=\sqrt{\frac{1}{5}\cdot ((30-52.5)^2+(40-52.5)^2+(60-52.5)^2+(80-52.5)^2+(20-52.5)^2+(85-52.5)^2}\\\\s=\sqrt{\frac{1}{5} *3587.5}=\sqrt{717.5}=26.8$

Then, we can calculate the standard error of the mean as:

$\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}=\frac{26.8}{6}= 4.5$

6 0

3 years ago

Convert:<br> 42 centigrams 6 milligrams =<br> 1<br> milligrams

Naddik [55]

Answer:

centigram is 'bigger.'

Well, if you look on the metric scale it is apparent that 1 mg = 0.1 (or 1/10) cg suggesting that a milligram is the smaller value.

6 0

3 years ago