The empirical formula of metal iodide : CoI₃(Cobalt(III) Iodide)
<h3>Further explanation</h3>
13.02 g sample of Cobalt , then mol Co(MW=58.933 g/mol) :

Mass of metal iodide formed : 97.12 g, so mass of Iodine :

Then mol iodine (MW=126.9045 g/mol) :

mol ratio of Cobalt and Iodine in the compound :
Answer:
The force of the gases pushes downward at the same time that the gases push the rocket upwards. 1.
Explanation:
The name transition metal refers to the position in the periodic table of elements. The transition elements represent the successive addition of electrons to the d atomic orbitals of the atoms. In this way, the transition metals represent the transition between group 2 (2A) elements and group 13 (3A) elements.
Answer: 2.19x10^25 atoms
Explanation:
Molar Mass of Neon = 20g/mol
1mole(20g) of Neon contains 6.02x10^23 atoms.
Therefore, 7.27x10^2g of Neon will contain x atoms i.e
X atoms = (7.27x10^2x6.02x10^23)/20 = 2.19x10^25 atoms
Rows of elements are called periods. The period number<span> of an element signifies the highest unexcited energy level for an electron in that element.
</span>Columns of elements help define element groups<span>. </span>Elements within a group share<span> several common properties. Groups are elements have the same outer electron arrangement.</span>