According to boyle p1v1=p2v2
So 3*4=6*x so x=2
Answer:
Three double bonds and no lone pairs of electrons- trigonal planar
Two single bonds and two lone pairs of electrons-bent
Five single bonds and no lone pairs of electrons- trigonal bipyramidal
Three single bonds and one lone pair of electrons- trigonal pyramidal
Two double bonds and no lone pairs of electrons - linear
Four single bonds and no lone pairs of electrons- tetrahedral
Six single bonds and no lone pairs of electrons- octahedral
Explanation:
The valence shell electron pair repulsion theory gives a description of the shape of a molecule based on the number of regions of electron density present on the valence shell of the central atom of the molecule.
The molecules are distorted away from the shape predicted on the basis of the VSEPR by the presence of lone pairs on the valence shell of the central atom in the molecule. In the absence of lone pairs, the shape of a molecule is exactly the shape predicted on the basis of the VSEPR theory.
So the solution inside doesn't splash
Answer:
Compound 1 is molecular
Compound 2 is ionic
Compound 3 can't really be decided
Explanation:
A molecular substance does not conduct electricity, has very low melting and boiling points and is held together by very weak intermolecular forces.
An ionic substance conducts electricity in solution or in molten state but never in the pure solid state, has a high melting and boiling point and has a dull appearance most times.
Compounds 1 shows the properties of molecular substances hence it are designated as such.
On the other hand, compound 2 shows the properties of an ionic substance and is also designated as such.
We can't really decide on compound 3 because it shows some properties of ionic substances and some properties of molecular substances.
